how to convert the string to integer in java if the string is like String str=“ 1234”;?


Matias
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how to convert the string to integer in java if the string is like this:


String str=" 1234";

note there is space in the beginning of the string. i tried Integer.parseTnt(str) method. But java shows NumberFormatException. Help me how to do?


Related to : how to convert the string to integer in java if the string is like String str=“ 1234”;?
how to convert the string to integer in java if the string is like String str=“ 1234”;?
Java

how to convert the string to integer in java if the string is like this:


String str=" 1234";

note there is space in the beginning of the string. i tried Integer.parseTnt(str) method. But java shows NumberFormatException. Help me how to do?


How can I split a String into a String array for each character, while grouping a “minus” sign with the integer that follows it?
Java

Here's what I've done:


while (sc.hasNext()) {
String sLine = sc.nextLine();
sLine.replaceAll("s", "");
String[] scanned = sLine.split("");

My input is going to be something like this:


IF (2 -2 +) (3 2 *) (-1 4 +) (5 3 *)

What this means is irrelevant, but what the scanner does is store it in a string "as is", first of all. Then I use the replaceAll function to remove all whitespace. I am then left with:


IF(2-2+)(32*)(-14+)(53*)

I then interpret this code using java and perform the calc

How to convert string “0671” or “0x45” into integer form with 0 and 0x in the beginning
Java

I wanted to make my own encryption algorithm and decryption algorithm , encryption algorithm works fine and converts ascii value of the characters into alternate hexadecimal and octal representations. But when I tried decryption, problem occured as it return int('0671') = 671, as 0671 is string type in the following code. Is there a method to convert "ox56" into integer form??????


NOTE: Following string is alternate octal and hexa of ascii value of char.


///////////////DECRYPTION///////
l="01630x7401620x6901560x67"
f=len(l)
k=0
d=0
x=[]
for i in range(0,f,4):
g=l[i:i+4]
print g
where can I see the print string when i add the code “System.out.println(”test string“);” in NameNode.java file?
Java

Under NameNode.java file


Try to added test code of print string in main() function, the code as below:


System.out.println("test string");


where can I see the print string?


*code compiler successful and used new generation file(hadoop-core-1.0.4.jar) replace to each node.
*All daemon has restart. but not found the print string on terminal.




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