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How to insert a pair of std::pair inside another std::pair?
by MD. in Programming Languages

I'm declaring a map of string to a pair of pairs as follow:


std::map<std::wstring,
std::pair<std::pair<long, long>,
std::pair<long, long>>> reference;

And I initialize it as:


reference.insert(L"First",
std::pair<std::pair<long, long>,

c++: How to transform a map iterator which point to pair into a “regular” pair pointer
by David Mercer in Programming Languages

those are the maps:


multimap<SortKey,T> firstMap;
multimap<SearchKey,pair<SortKey,T>*> secondMap;
template <class T,class SortKey, class SearchKey> bool GarageDataBase<T,SortKey,SearchKey>::Add(T data,SortKey key1, SearchKey key2)
{
multimap<SortKey,T>::iterator it;
it=(firstMap.insert(pair<SortKey,T>(key1,data

ADOdb fetchRow function is returning both columns name value pair and index(0,1,..),value pair
by Igor Carron in Programming Languages

it fetches like this


Array
(
[0] => ABC
[NAME] => ABC
[1] => 33
[AGE] => 33
[3] => M
[GENDER] => M
[4] => LA
[CITY] => LA
[5] => OH
[STATE] => OH
)

How to get either case like


Array
(
[0] => ABC
[1] => 33
[2] => M
[3] => LA
[4] => OH
)


How do I create a set with std::pair thats sorted based on the ::second pair member using bind
by bikefixxer in Programming Languages

I know I could use the following:


template <typename Pair>
struct ComparePairThroughSecond : public std::unary_function<Pair, bool>
{
bool operator ()(const Pair& p1, const Pair& p2) const
{
return p1.second < p2.second;
}
};
std::set<std::pair<int, long>, ComparePairThroughSecond>

How to Knit a Pair of Fingerless Gloves Using a Pair of Circular Needles
by Alec in Hobbies, Games & Toys
If you're working with your hands in a chilly indoor environment, fingerless gloves were designed to keep your hands warm in those situations. Your fingertips are free to type or perform delicate tasks. And knitting fingerless gloves allows you to indulge in luxury yarns or sample new yarns, as even the largest fingerless gloves don't use more than two balls of yarn. The wrist and back of the hand

Check 30 minute interval pair and ignore if pair not found
by Ph33zy in Programming Languages

I'm expecting the following sequence of time data in 30 minute interval from another system. I need to make this 30 minute pair in to one hour interval:


e.g.
Source Data:


Start:7:00
End: 7:30
Start:7:30
End: 8:00
Start:8:00
End: 8:30
Start:8:30
End: 9:00

Convert in to hour data like below:


Sta

How to turn an old pair of jeans into a cute pair of capris
by cubeless in Hobbies, Games & Toys
With an old pair of jeans you can make just about anything fashionable. In this case, you will be making a pair of capris. Using one pair of jeans, you can create one of three very chic capri styles. Read on to learn how to turn an old pair of jeans into a cute pair of capris.Difficulty:Moderately EasyInstructions Things You'll Need
Old jeans
Scissors
Sewing needle and thread or hemmi

Is there any difference using {} pair or () pair when define function-like macro in C?
by BooTeK in Web Design

For example:


#define FOO(x) (printf(x))

and


#define FOO(x) {printf(x)}

It seems that both are viable for preprocessing, but which is better?


How to make an awesome pair of shorts out of an old pair of jeans
by Igal in Hobbies, Games & Toys
Have you ever purchased a pair of perfectly fitting jeans, just to have them shrink to a length that makes them just a little too short to wear? Instead of writing them off, turn them into an awesome pair of excellent fitting shorts!!Difficulty:Moderately EasyInstructions Things You'll Need
Old pair of great fitting jeans you can no longer wear because they are too short.
Scissors
Rul

How to generate Random pair without repeating the same pair again in android
by Viren in Android

Is this possible or not?


Can anyone tell me how to generate a random pair when I call the app?


for example: i have 0-5 images and i have 10 buttons when i call the app the images are paired like this


1-9=image0
2-7=image3
3-8=image2
4-6=image4
5-10=image1

If anyone known the a


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