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php function return an array

By : user8014169
Date : May 05 2020, 10:00 AM

I have issue about return value, now i can return back with variable but it automatic separate it become 4 array. Below is my data when i used json_decode $json_template = json_decode($json_body,true); function

    "username": "",
    "password": "",
    "environment": "900"

then , i need to change the value by merge variable so i use Map function:

$map = new Map($json_template);
$maps = $map->map(function($key, $value){
            if($key == 'password'){
                 $value = 'test';
            return array($key=>$value);

It result is become:

        "username": ""
        "password": "test"
        "environment": "900"

But i expected my result will come out like

    "username": "",
    "password": "test",
    "environment": "900"

what should i add or change the code?

Answer :

From doc about the map method:

Returns the result of applying a callback to each value


The callable should return what the key will be mapped to in the resulting map.

It mean you only need to return modified value instead of an array {key:value}.

This is a working example on my pc using (PHP 7.0 CLI):

$json_template = json_decode(' { "username": "", "password": "", "environment": "900" } ', true); $map = new \Ds\Map($json_template); $maps = $map->map(function($key, $value){ if($key == 'password'){ $value = 'test'; } return $value; }); print_r($maps->toArray());


    [username] =>
    [password] => test
    [environment] => 900

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