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Generate a fixed number of 1s on random positions


Generate a fixed number of 1s on random positions

By : Md Waseem
Date : November 15 2020, 04:01 AM
like below fixes the issue Is there a way possible to get the number 1 occurring n Number of times randomly, in a vector that should contain only numbers 0 and 1? , Try this:
code :
#include <iostream>
#include <vector>
#include <algorithm>
#include <random>

void print_v (const std::vector <int>& v)
{
    for (int i : v)
        std::cout << i;
    std::cout << "\n";
}

int main()
{
    std::vector <int> v;

    v.push_back (1);
    v.push_back (1);
    v.push_back (0);
    v.push_back (0);
    v.push_back (0);
    print_v (v);

    std::random_device rd;
    std::mt19937 g (rd ());    
    std::shuffle (v.begin (), v.end (), g);
    print_v (v);
}
11000
00011


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generate a random number with fixed length

generate a random number with fixed length


By : user3934765
Date : March 29 2020, 07:55 AM
To fix the issue you can do I want to generate a random number with in two range, and i want it to have fixed length. I don't want to limit the range as offered i How to generate random number with the specific length in python
code :
import random
'{0:05}'.format(random.randint(1, 100000))
Trying to Generate a variable number of coloured patches at random positions

Trying to Generate a variable number of coloured patches at random positions


By : Jasper Ioverthoughtt
Date : March 29 2020, 07:55 AM
this will help I would like to control the number of black patches that are generated(for example generate 10 black patches in random positions). Right now I am generating a random amount in random locations. I am using netlogo. , Use n-of:
code :
ask patches [set pcolor gray]

ask n-of 10 patches [set pcolor black]
How to generate a random number with fixed length only with 0's and 1's and a fixed amount of 1's?

How to generate a random number with fixed length only with 0's and 1's and a fixed amount of 1's?


By : user3686335
Date : March 29 2020, 07:55 AM
it fixes the issue This should work for you:
No need for a loop. Just first fill an array with 1's $many times. Then array_merge() the array with the 0's which you fill up until $length elements.
code :
<?php

    $min = 0;
    $max = 1;

    $many = 3;
    $length = 6;

    $arr = array_fill(0, $many, $min);
    $arr = array_merge($arr, array_fill($many, $length-$many, $max));
    shuffle($arr);

    echo implode("", $arr);

?>
011010
Generate a random number and add 0 before it to ensure fixed number of digits

Generate a random number and add 0 before it to ensure fixed number of digits


By : Hai chau
Date : March 29 2020, 07:55 AM
wish of those help so I am trying to generate a random number. I am going to append the day and month as integers before the random number. This I am able to do by using the following code. , Two possible solutions.
code :
Calendar calendar = GregorianCalendar.getInstance();
int num = 0;
num += (calendar.get(Calendar.MONTH) + 1) * 10_000_000;
num += calendar.get(Calendar.DAY_OF_MONTH) * 100_000;
num += your_random_number_lower_100000
Calendar calendar = GregorianCalendar.getInstance();
String randomDigits = String.format("%d%02d%05d", 
        calendar.get(Calendar.MONTH) + 1,
        calendar.get(Calendar.DAY_OF_MONTH),
        your_random_number_lower_100000
);
How to generate a random normal distribution of a fixed number of positive integers that sum up to a fixed value

How to generate a random normal distribution of a fixed number of positive integers that sum up to a fixed value


By : Aaron Lee
Date : March 29 2020, 07:55 AM
This might help you One approach might be the following: Think of an array of (sum − 1) bits. Choose (n − 1) of them as 1, the rest 0. Now between the ones, as well as before the first one and after the last, you have runs of zero or more zeros. Take the length of each run, add 1 (to turn non-negative into positive) and you have n positive integers that add up to sum.
From an implementation point of view, you don't really need that array; all you need is the positions of the ones. Make sure they are distinct, and make sure they are in the range between 0 and sum − 1 exclusive.
code :
def random_partition(n, sum):
  indices = [-1] + sorted(random.sample(range(sum - 1), n - 1)) + [sum - 1]
  return [indices[i + 1] - indices[i] for i in range(n)]
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