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Function returning different value than what is in function body before return statement


Function returning different value than what is in function body before return statement
» cpp » Function returning different value than what is in function body before return statement
By : Jiří Jinger
Date : November 17 2020, 04:01 AM
it should still fix some issue I found the problem in my function, the solution was just swapping one variable:
code :
vector<string> findPath(map<string, set<string>> mst, string src, string dest, vector<string> path) {
    if(src == dest) {
        cout << "Function path size: " << path.size() << endl;
        return path;
    }
    set<string> possible = mst[src];
    for(vector<string>::iterator it = path.begin(); it != path.end(); it++) {
        if(possible.find(*it) != possible.end())
            possible.erase(*it);
    }
    for(set<string>::iterator it = possible.begin(); it != possible.end(); it++) {
        vector<string> a = path;
        if(find(a.begin(), a.end(), src) == a.end())
                a.push_back(src);
        vector<string> p = findPath(mst, *it, dest, a);
        if(p[0] != "randValue") {
            /**
             * RETURN p INSTEAD OF path
             */
            return p;
        }
    }
    vector<string> p = path;
    p[0] = "randValue";
    return p;
}


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function returning std::string crashes without return statement, unlike a function returning int without return statemen

function returning std::string crashes without return statement, unlike a function returning int without return statemen

By : Mubashir Ahmed
Date : March 29 2020, 07:55 AM
seems to work fine , Both are undefined behaviors, even noCrash can crash.
The body of constexpr function not a return-statement

The body of constexpr function not a return-statement

By : gtjamieson
Date : March 29 2020, 07:55 AM
I hope this helps . C++11's constexpr functions are more restrictive than that.
From cppreference:
code :
constexpr int func (int x) { return x < 0 ? -x : x; }

static_assert(func(42) == 42, "");
static_assert(func(-42) == 42, "");

int main() {}
When returning an anonymous function from a function, is the function in the return statement a function declaration or

When returning an anonymous function from a function, is the function in the return statement a function declaration or

By : Patrick
Date : March 29 2020, 07:55 AM
With these it helps So I did some digging in the ECMAScript Language Specification and came to the conclusion that the anonymous function that's being returned is a function expression... and it really seems quite simple now. When defining a function using a function declaration, the identifier isn't optional and so an anonymous function can't be defined using a function declaration. Anonymous functions can only be defined using function expressions because with function expressions, the identifier is optional.
I also said this...
Arrow function body vs. returning value. ()=>{return value;} vs. ()=>value;

Arrow function body vs. returning value. ()=>{return value;} vs. ()=>value;

By : Ray
Date : March 29 2020, 07:55 AM
help you fix your problem One difference is that returning object literals using the implicit return syntax requires the object literal to be wrapped in parenthesis.
How is the body passed to the return statement in this function

How is the body passed to the return statement in this function

By : Denis Langlais
Date : January 02 2021, 06:48 AM
wish of those help handleSuccess creates and returns a function (using arrow function syntax). The call to it is being run (as a result of the (res) after it), and then the funtion it returns is being called with the object created by the object initializer.
code :
//  vvvvvvvvvvvvvvvvvv---------------------------- creates the function
    handleSuccess(res)({ message: 'message' });
//                    ^^^^^^^^^^^^^^^^^^^^^^^^ --- calls the function

const handler = handleSuccess(res);
handler({ message: 'message' });
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