 What is Operator overloading? Is operator overloading a specific feature to C++ and not available in Java
By : Ahmed Matter
Date : March 29 2020, 07:55 AM
With these it helps Operator overloading is a feature where the language allows you to define operators for your own types, so that you can write e.g. o1 + o2 where o1 and o2 are instances of your own type, instead of built-in types. Operator-overloading is not specific to C++, but it's not available in java. Here's an example in Python: code :
class Vector3D():
def __init__(self, x, y, z):
self.x = x
self.y = y
self.z = z
def __repr__(self):
return "Vector<%f,%f,%f>" % (self.x, self.y, self.z)
def __add__(self, other):
return Vector3D(self.x + other.x,
self.y + other.y,
self.z + other.z)
a = Vector3D( 1, 2, 3)
b = Vector3D(-1,-2,-3)
print a+b # Vector<0.000000,0.000000,0.000000>
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Operator overloading clarification
By : Pablo Felix Estevez
Date : March 29 2020, 07:55 AM
I hope this helps you . Example one must be a non-member operator. Because operator+ has one or two arguments if a non-member but zero or one if a member. It has no special access to Jazz, it's the same as any other function in that respect. If you want to give it special access to Jazz you would declare it a friend (again just like any other function).
Example two must be a member, that's just a rule of C++, operator= must be a member function. You don't have to declare a copy constructor as well. It's just that's it's very common that if you need a copy constructor you will also need an assignment operator and vice versa.
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Clarification on smart pointer's operator* and operator-> overloading
By : Alex
Date : March 29 2020, 07:55 AM
I wish this helpful for you In C++, when you evaluate a function, you end up with a value (unless the function's return type is void). The type of a value is always an object type. So when you say f(), that expression is a value of type T. However, there are different categories of value: code :
T f(); => f() is a prvalue, passed along by copy
T & f(); => f() is an lvalue, the same object that is bound to "return"
T && f(); => f() is an xvalue, the same object that is bound to "return"
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 && operator overloading and assignments in C# - Clarification?
By : tshsu
Date : March 29 2020, 07:55 AM
wish help you to fix your issue Firstly, don't forget that this is deliberately bizarre code, used to find a corner case. If you ever find a type that behaves like this in a genuine program, find the author and have a quiet word with them.
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Operator overloading:how in unary operator overloading function return is working in this code?
By : fserron
Date : March 29 2020, 07:55 AM
should help you out
if a instance of Distance is to be returned in operator-() function shouldn't it be returned like new Distance(feet,inches)
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code :
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