Sqlalchemy dialects DATERANGE vs. psycopg2.extras.DateRange changing bounds

Sqlalchemy dialects DATERANGE vs. psycopg2.extras.DateRange changing bounds

By : rdv
Date : November 20 2020, 04:01 AM
seems to work fine The difference is that
psycopg2.extras.DateRange represents a Postgresql daterange value. You define bounds on a per value basis. sqlalchemy.dialects.postgresql.DATERANGE is from SQLAlchemy, as should be clear from the qualified name, and represents a Postgresql daterange type, as used in a CREATE TABLE statement etc. It does not care about the bounds of the values you store in a column having this type.
code :

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Hibernate. Check if daterange is within another daterange

Hibernate. Check if daterange is within another daterange

By : krunalseo
Date : March 29 2020, 07:55 AM
To fix the issue you can do If I understand you question correctly - That is, that the event availability should lie completely within the search date range - then it should boil down to this:
If you ensure that "availableFromDate.before(availableToDate)" and "searchFromDate.before(searchToDate)" - which you should do anyway in this case - Then both your availableFromDate and your availableToDate have to be in the search date range.
code :
criteria.add(Restrictions.between("availableFromDate", searchFromDate, searchToDate));
criteria.add(Restrictions.between("availableToDate", searchFromDate, searchToDate));
Add daterange to Google Search Appliance without displaying daterange in input

Add daterange to Google Search Appliance without displaying daterange in input

By : user3830814
Date : March 29 2020, 07:55 AM
Python / SQLAlchemy format DateRange object

Python / SQLAlchemy format DateRange object

By : user1690147
Date : March 29 2020, 07:55 AM
will be helpful for those in need SQLAlchemy documentation hints that the range types are a Psycopg feature, so looking at their documentation for the objects in question you will find that Range objects have attributes lower and upper that hold the bounds. With them it is straightforward to produce a list of tuples:
code :
fmt = '%Y-%m-%d'
bookings = [(format(bdate.lower, fmt), format(bdate.upper, fmt))
            for bdate in room.RoomObject_addresses_UserBooksRoom]
Python postgreSQL sqlalchemy query a DATERANGE column

Python postgreSQL sqlalchemy query a DATERANGE column

By : manju
Date : November 11 2020, 04:01 AM
wish helps you I have a booking system and I save the booked daterange in a DATERANGE column: , The query
code :
the_daterange_lower = datetime.strptime(the_daterange[0], '%d.%m.%Y')
the_daterange_upper = datetime.strptime(the_daterange[1], '%d.%m.%Y')

bookings = UserBooks.query.\
    filter(UserBooks.booked_date.lower >= the_daterange_lower,
           UserBooks.booked_date.upper <= the_daterange_upper).\
the_daterange_lower = datetime.strptime(the_daterange[0], '%d.%m.%Y').date()
the_daterange_upper = datetime.strptime(the_daterange[1], '%d.%m.%Y').date()

the_daterange = DateRange(the_dateranger_lower, the_daterange_upper)

bookings = UserBooks.query.\
bookings = db_session.execute(
    'SELECT * FROM usersbookrooms WHERE booked_date && %s',
    (DateRange(the_daterange_lower, the_daterange_upper),))
bookings = db_session.execute(
    'SELECT * FROM usersbookrooms WHERE booked_date && %s::daterange',
    (f'[{the_daterange_lower}, {the_daterange_upper})',))
bookings = db_session.execute(
    'SELECT * FROM usersbookrooms WHERE booked_date && daterange(%s, %s)',
    (the_daterange_lower, the_daterange_upper))
Count days of daterange in daterange

Count days of daterange in daterange

By : Ames Belt
Date : March 29 2020, 07:55 AM
it helps some times You can do this by taking the intersection of the two ranges using GREATEST on the start dates and LEAST on the end dates. Intersecting ranges will return a positive number, non-intersecting a negative one. So we use GREATEST again to zero out negative values to get the overlap. For example:
code :
  `Start_date` DATE,
  `End_date` DATE

  (`Start_date`, `End_date`)
  ('2020-06-03', '2020-12-31'),
  ('2014-09-08', '2015-09-07'),
  ('2015-01-15', '2015-02-01');

SET @start = '2015-01-20';
SET @end = '2015=02-04';
SELECT GREATEST(TIMESTAMPDIFF(DAY, GREATEST(Start_Date, @start), LEAST(End_Date, @end))+1, 0) AS overlap
FROM test;
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