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Named Type association with Typescript


Named Type association with Typescript

By : user2185124
Date : November 20 2020, 04:01 AM
I hope this helps . Type guards don't support narrowing the type of a different value then the one checked.
What we can do is change the callback to take in an object that is a union where a member of a union has the form { type: P, value T[P] } where T is the map type and P in turn every property of T
code :
// Type that creates a union using the distributive property of union types.
type TypeUnion<T> = keyof T extends infer P ? // Introduce an extra type parameter P to distribute over
  P extends any ? { type: P, value: T[P] } :  // Take each P and create the union member
  never : never;

interface Thing<TMap extends { [k: string]: any }> {
  get(handler: (v: TypeUnion<TMap>) => unknown): unknown
}
declare const thing: Thing<Types>


interface Types {
  num: number,
  dat: Date,
  str: string
}

thing.get(o => { // o is  { type: "num"; value: number; } | { type: "dat"; value: Date; } | { type: "str"; value: string; }
  if (o.type === 'num') {
    o.value // number
  } else if (o.type === 'dat') {
    o.value // Date
  } else if (o.type === 'str') {
    o.value // string
  }
})
type TypeUnion<T> = {
  [P in keyof T] : { type: P, value: T[P]}
}[keyof T]


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Symfony2 + Doctrine Association Error: Class Game has no association named home

Symfony2 + Doctrine Association Error: Class Game has no association named home


By : user2316319
Date : March 29 2020, 07:55 AM
I hope this helps you . According to doctrine documentation your mapping should look like:
Game.orm.yml:
code :
Travel\Bundle\TravelBundle\Entity\Game:
    type: entity
    repositoryClass: Travel\Bundle\TravelBundle\Entity\GameRepository
    oneToOne:
        home:
            targetEntity: Travel\Bundle\TravelBundle\Entity\Team
            joinColumn:
                name: home
                referencedColumnName: id
        away:
            targetEntity: Travel\Bundle\TravelBundle\Entity\Team
            joinColumn:
                name: away
                referencedColumnName: id
Typescript: How can I refer to an anonymous type that is a child of a named type?

Typescript: How can I refer to an anonymous type that is a child of a named type?


By : Andrea L.
Date : March 29 2020, 07:55 AM
seems to work fine I am using apollo-codegen to generate TypeScript types from the GraphQL queries embedded in the tsx files in my project. An example of a generated type is: , You can use the bracket notation
code :
renderHelper(node: MooQuery['wines']['edges'][0]['node']) { // this should work
  //                                         ^^^ Don't forget the 0 for the array
}
export type MooQuery = {
  wines:  {
    edges:  Array<{node: MooNode} | null > | null,
  } | null,
};

export type MooNode = {
    nodeId: string,
    wineName: string | null,
    wineryId: number | null,
    vintageId: number | null,
    uomId: number | null
}
Typescript: Named property type must be assignable to string indexer type

Typescript: Named property type must be assignable to string indexer type


By : davide vincitorio
Date : March 29 2020, 07:55 AM
this will help Based on the error, that is not the only definition of IJQuery. As far as I can tell this is specific to your project and is not part of the JQuery library.
Form the error, there is probably a definition of IJQuery that contains an indexer:
code :
interface IJQuery {
    [name: string]: HTMLElement
}
interface IJQuery {
    addRecordInline(object: any) : void; // Not ok
    anElement: HTMLElement // OK
}
Factory-girl: 'association' named column overlap with Factory method named 'association'

Factory-girl: 'association' named column overlap with Factory method named 'association'


By : itagaki
Date : March 29 2020, 07:55 AM
it should still fix some issue You could assign it in an f.after_create. Not as elegant though. Renaming the column might not be a bad idea either.
Typescript interface with named property and arbitrarily-named index properties of different type

Typescript interface with named property and arbitrarily-named index properties of different type


By : aaa
Date : March 29 2020, 07:55 AM
Hope that helps You can do something like this (I don't know if it will work in TS v1.5):
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