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Cumulative sum of array items


Cumulative sum of array items

By : mini
Date : November 21 2020, 04:01 AM
fixed the issue. Will look into that further Option 1
So if you want to get exact results as in your examples, you can use this method. It will return you an array of partial sums, that you can later sum up to get the result:
code :
private static long[] CumulativeSums(long[] values)
{
    if (values == null || values.Length <= 1) return new long[0];

    var results = new long[values.Length];
    results[0] = values[0] + values[1];

    for (var i = 1; i < values.Length - 1; i++)
    {
        results[i] = results[i - 1] + values[i + 1];
    }

    return results;
}
var numbers = new long[] { 12, 15, 17, 19 };
var sumOfCumulativeSums = CumulativeSums(numbers).Sum();
public static long[] CumulativeSums(long[] values)
{
    if (values == null || values.Length == 0) return new long[0];

    var results = new long[values.Length];
    results[0] = values[0];

    for (var i = 1; i < values.Length; i++)
    {
        results[i] = results[i - 1] + values[i];
    }

    return results;
}


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MySQL cumulative count open items

MySQL cumulative count open items


By : Tv Esport
Date : March 29 2020, 07:55 AM
it fixes the issue Here is one easy method. Get the unique dates and then use correlated subqueries:
code :
select d.dte,
       (select count(*) from t where t.created_at < d.dte + interval 1 day
       ) as total,
       (select count(*) from t where t.closed_at < d.dte + interval 1 day
       ) as closed,
       (select count(*) from t
        where t.created_at < d.dte + interval 1 day and
              (t.closed_at is null or t.closed_at >= d.dte + interval 1 day)
       ) as total
from (select date(created_at) as dte from t
      union -- on purpose to remove duplicates
      select date(closed_at) from t
     ) d;
How to pick random items through cumulative probability?

How to pick random items through cumulative probability?


By : Jose Mourinho
Date : March 29 2020, 07:55 AM
hop of those help? I find it easier to work with integers in this type of problem, so I'll work with:
code :
Food - 10
Weapons - 5
Enemy - 5
Trap - 3
Food - 0..9 giving 10 options.
Weapons - 10..14 giving 5 options.
Enemy - 15..19 giving 5 options.
Trap - 20..22 giving 3 options.
function pickFWET()

  pick <- randomInRange(0 to 22);

  if (pick < 10) return FOOD;
  if (pick < 15) return WEAPONS;      
  if (pick < 20) return ENEMY;
  if (pick < 23) return TRAP;

  // If we reach here then there was an error.
  throwError("Wrong pick in pickFWET");

end function pickFWET
Get all items in list until cumulative sum reaches a limit value

Get all items in list until cumulative sum reaches a limit value


By : user3336722
Date : March 29 2020, 07:55 AM
this one helps. I've a List>. This list is guarantee sorted by DateTime. Now I want to get all items which are included in the cumulative sum until a limit value is reached. What is the most elegant way to do this? , I think I would do something like this:
code :
var list = new List<Tuple<DateTime, double>>
{
    ....
};

var sum = 0d;
var limit = 10d;

var result = list.TakeWhile(x => (sum += x.Item2) < limit).ToList();
Cumulative sum of items in a dictionary

Cumulative sum of items in a dictionary


By : user3429892
Date : March 29 2020, 07:55 AM
I wish this help you You can use the fact that collections.Counter objects update in the way you want to accumulate:
code :
import collections


def cumulative_elementwise_sum(ds):
    result = collections.Counter()
    for d in ds:
        result.update(d)
        yield dict(result)
>>> x = [
...    {'t': 1, 'a': 1, 'b': 3},
...    {'t': 2, 'a': 2, 'b': 4},
...    {'t': 1, 'a': 4, 'b': 1, 'd': 2},
... ]
>>> list(cumulative_elementwise_sum(x))
[{'t': 1, 'a': 1, 'b': 3},
 {'t': 3, 'a': 3, 'b': 7},
 {'t': 4, 'a': 7, 'b': 8, 'd': 2}]
def updated(c, items):
    c.update(items)
    return c

map(dict, itertools.accumulate(x, updated, initial=collections.Counter()))
import functools

>>> functools.reduce(updated, x, collections.Counter())
Counter({'t': 4, 'a': 7, 'b': 8, 'd': 2})

# dict version
>>> dict(functools.reduce(updated, x, collections.Counter()))
{'t': 4, 'a': 7, 'b': 8, 'd': 2}
how to cumulative sum the unique items in pandas?

how to cumulative sum the unique items in pandas?


By : RajasekharReddy
Date : March 29 2020, 07:55 AM
I hope this helps you . I have a pandas df that contains date level data and , You need one more step to get the cumsum_unique_id
code :
s=df.groupby(['class', 'MONTH_YEAR']).agg({'id': 'nunique', 'accnt_id': 'nunique'})

s1=df.drop_duplicates(['class','accnt_id']).\
     groupby(['class', 'MONTH_YEAR']).accnt_id.count().groupby(level=0).cumsum()
s['cumsum_unique_id']=s1
s
Out[39]: 
                   id  accnt_id  cumsum_unique_id
class  MONTH_YEAR                                
fruits 2012-01      2         3                 3
       2012-02      1         2                 4
vege   2011-01      1         1                 1
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