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How to get distinct values from set of rows matching condition


How to get distinct values from set of rows matching condition

By : kavita pamnani
Date : November 21 2020, 04:01 AM
seems to work fine The reason you get an error is because you apply the Where condition on a projected sequence that includes only ProjectId. You should use Where before Select.
To get the distinct values, use the Enumerable.Distinct method:
code :
return await _context.CustomerSatisfactionResults
   .Where(x => x.AccountId == accid && x.Year == year && x.Quarter == qurter)
   .Select(x => x.ProjectId)
   .Distinct()
   .ToListAsync();


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postgresql :: retrieve row matching exact condition or number of rows matching part of condition

postgresql :: retrieve row matching exact condition or number of rows matching part of condition


By : vnavarro
Date : March 29 2020, 07:55 AM
I wish this helpful for you I have table "permission" like , Try:
code :
SELECT count(*) as total_count, --count of permission records for object
       bool_or(user_id = 1 AND readable) as user_readable, -- user has read permission, null if no permission record
       bool_or(user_id = 1 AND writable) as user_writable, -- user has write permission, null if no permission record
FROM permission
WHERE object_id = 123456
SELECT total_count = 0 OR user_readable as readable,
       total_count = 0 OR user_writable as writable
FROM (first select here)
Mysql find distinct values from rows matching multiple values in another field

Mysql find distinct values from rows matching multiple values in another field


By : Andrew McKeever
Date : March 29 2020, 07:55 AM
this one helps. You will want to use the following which selects all rows that have an id2 with a value of 3, 4 or 5 and then applies a group by with a having clause to make sure that you return 3 distinct id2 values:
code :
select id1
from yourtable
where id2 in (3, 4, 5)
group by id1
having count(distinct id2) = 3
MySQL Select Distinct and count number of each distinct condition matching criteria

MySQL Select Distinct and count number of each distinct condition matching criteria


By : john
Date : March 29 2020, 07:55 AM
Hope this helps If I understand correctly, this is just a group by query with conditional aggregation:
code :
select date(start_time), sum(filled = 0) as NumAvailable
from Appointment
group by date(start_time)
order by date(start_time);
Pyspark DataFrame select rows with distinct values, and rows with non-distinct values

Pyspark DataFrame select rows with distinct values, and rows with non-distinct values


By : Surge
Date : March 29 2020, 07:55 AM
Any of those help You can count the number of rows partitionBy record_id, if the record_id has only one row, mark it as unique:
code :
from pyspark.sql.window import Window
import pyspark.sql.functions as F

df.withColumn("unique", (F.count("record_id").over(Window.partitionBy("record_id")) == 1).cast('integer')).show()
+---------+-----------+-----------+------+
|record_id|        foo|        bar|unique|
+---------+-----------+-----------+------+
|        3|random text|random text|     1|
|        1|random text|random text|     0|
|        1|random text|random text|     0|
|        2|random text|random text|     0|
|        2|random text|random text|     0|
+---------+-----------+-----------+------+
How do I filter multiple rows with matching column values based on all rows meeting a certain condition? [R]

How do I filter multiple rows with matching column values based on all rows meeting a certain condition? [R]


By : lgrunda
Date : March 29 2020, 07:55 AM
To fix the issue you can do I have a data table called iso: , Try the following:
code :
library(dplyr)

iso <- setDT(iso)[with(iso, (is_NL == 0 & counts/nrows < 50) | (is_NL %in% c(1,2) & counts/nrows > 50)),][, triplet := .N, by = .(variant_id, transcript_id)][triplet == 3, ][, triplet := NULL]
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