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Why do I need dynamic memory allocation if I can just create an array?


Why do I need dynamic memory allocation if I can just create an array?

By : Dael Ceja
Date : November 21 2020, 04:01 AM
hop of those help? According to this (emphasis mine):
code :


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Task to create flexible (dynamic memory allocation) array

Task to create flexible (dynamic memory allocation) array


By : Ken
Date : March 29 2020, 07:55 AM
Any of those help We've been given a task to write a dynamic data structure in C. I'm still incredibly new to C and I would really appreciate it if someone could give me some pointers (lol) on what I'm doing wrong / what I should read more about.
code :
void flexarray_add(flexarray a, char item){
    if(a->size == a->capacity) grow(a);
    a->array[a->size - 1] = item;
    a->size++;    
}
void flexarray_add(flexarray *a, char item){
    if(a->size == a->capacity) grow(a);
    a->array[a->size] = item;
    a->size++;    
}
void flexarray_print(flexarray a){
    int i;
    printf("[");
    for(i = 0; i < a->size - 1; i++){
        printf("%c,", a->array[i]);
    }
    printf("%c]\n", a->array[i + 1]);
}
void flexarray_print(flexarray *a){
    int i;
    printf("[");
    for(i = 0; i < a->size; i++){
        printf("%c,", a->array[i]);
    }
    printf("]\n" );
}
struct buff {
     size_t size;
     size_t used;
     char *data;
     };
How to create live dynamic memory allocation in an array of numbers, while taking input?

How to create live dynamic memory allocation in an array of numbers, while taking input?


By : sergei mashkin
Date : March 29 2020, 07:55 AM
Hope that helps So My mission is to keep accepting numbers from users until the user input a negative number. My algorithm should be: 1)start in the size of 2. 2)double the size every time it reaches the end, free the older one. 3) stop when user hits negative number. , You should use malloc'ed arrays only with realloc
Here is code:
code :
#include <stdio.h>
#include <stdlib.h>

int main(void) {
    int *nums;
    size_t size = 2;
    nums = malloc(size * sizeof(int));
    size_t i = 0;

    while (i < size && nums != NULL) {
        scanf("%d", (nums+i));
        if (nums[i] < 0)
            break;
        i++;
        if (i == size) {
            size *= 2;
            nums = realloc(nums, size * sizeof(int));
        }
    }

    if (nums == NULL) {
        puts("Error");
        return 1;
    } else {
        free(nums);
        puts("Stop");
        return 0;
    }
}
Dynamic memory allocation for 4 Dimensional c++ array to create HDF5 dataset

Dynamic memory allocation for 4 Dimensional c++ array to create HDF5 dataset


By : Pro Ryan
Date : March 29 2020, 07:55 AM
will help you I would suggest to allocate one contiguous chunk of memory, like this:
code :
int *data = new int[dataNumber * dataFilter * dataWidth * dataHeight];
delete []data;
data[((i*dataFilter + j)*dataWidth + k)*dataHeight + l];
how to create array of objects without dynamic memory allocation

how to create array of objects without dynamic memory allocation


By : animuS eSports
Date : March 29 2020, 07:55 AM
this will help You don't have to use new. You can create an array of Particles as you suggested yourself:
Trying to create an array of node pointers using dynamic memory allocation

Trying to create an array of node pointers using dynamic memory allocation


By : Amit Kumar
Date : March 29 2020, 07:55 AM
may help you . I'm currently trying to do something simple, turn my list of nodes into an array of pointers to the nodes, so that I could use it for another functionality. , These two lines are a little problematic:
code :
aryPtr[inc] = malloc(sizeof(myNode));
aryPtr[inc] = &(myList[z]);
aryPtr[inc] = malloc(sizeof(myNode));
aryPtr[inc] = &(myList[z]);
int a;
a = 5;
a = 10;
aryPtr[inc] = &myList[z];  // Make aryPtr[inc] point to myList[z]
aryPtr[inc] = malloc(sizeof(myNode));
*aryPtr[inc] = myList[z];  // Copy the structure itself
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