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How to check JSON string on contains field AND like value?


How to check JSON string on contains field AND like value?

By : pizaninja
Date : November 22 2020, 04:01 AM
may help you . You need to unnest your array in order to be able to use an operator on each element in there.
This can be done in a co-related subquery:
code :
select t1.*
from the_table t1
where exists (select *
              from jsonb_array_elements(t1.d) as x(e)
              where x.e ->> 'idNumber' like '21%');


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Jackson - Map JSON string field to class/pojo that has only one field (a string)

Jackson - Map JSON string field to class/pojo that has only one field (a string)


By : Igor Remenyuk
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further Use @JsonCreator for deserializing and use @JsonValue for Serializing. Have tested the code. Please make sure that getJsonString() is public method.
For example:
code :
public class User{
    private String username;

    @JsonValue
    public String getJsonString() {
         return username;
    }

    @JsonCreator
    private static User parseJson(String jsonStr) {
        User u = new User();
        u.username = jsonStr;
        return u;
    }

    public static void main(String[] args) {
        User u = new User();
        u.userName = "Niraj";

        ObjectMapper m = new ObjectMapper();
        String jsonString = m.writeValueAsString(u);
        User u1 = m.readValue(jsonString, User.class);
    }
}
How can i deserialize Json string where object's field's subclass is included in json string, using Java and Jackson lib

How can i deserialize Json string where object's field's subclass is included in json string, using Java and Jackson lib


By : Thắng Nguyễn
Date : March 29 2020, 07:55 AM
I hope this helps you . What you are trying to achieve is called polymorphic deserialization. Your example fails because Jackson needs to know what instance type should be constructed from JSON and placed to the list of instances. Please refer to this wiki page for detailed explanation.
I have modified you example to demonstrate how it could work. I've added the instance type information in the @type field in the JSON representation. Also I've made all the classes immutable using constructors annotated with the @JsonCreator annotation to create instances.
code :
public class JacksonPolymorphism {

    public static class BaseEntity {
        private final String id;

        protected BaseEntity(String id) {
            this.id = id;
        }
    }

    public static class Site extends BaseEntity {
        private final String siteName;
        private final List<Instance> instances;

        @JsonCreator
        public Site(@JsonProperty("id") String id,
                    @JsonProperty("siteName") String siteName,
                    @JsonProperty("instances") List<Instance> instances) {
            super(id);
            this.siteName = siteName;
            this.instances = instances;
        }

        @Override
        public String toString() {
            return "Site{" +
                    "siteName='" + siteName + '\'' +
                    ", instances=" + instances +
                    '}';
        }
    }

    @JsonTypeInfo(use = JsonTypeInfo.Id.NAME,
            include = JsonTypeInfo.As.PROPERTY,
            property = "@type")
    @JsonTypeName(value = "simple")
    public static class Instance extends BaseEntity {
        private final String name;

        @JsonCreator
        public Instance(@JsonProperty("instanceId") String id,
                        @JsonProperty("name") String name) {
            super(id);
            this.name = name;
        }

        @Override
        public String toString() {
            return "Instance{" +
                    "name='" + name + '\'' +
                    '}';
        }
    }

    @JsonTypeName("cloud")
    public static class CloudInstance extends Instance {
        private final String availabilityZone;
        private final String instanceType;


        public CloudInstance(@JsonProperty("instanceId") String id,
                             @JsonProperty("name") String name,
                             @JsonProperty("availabilityZone") String availabilityZone,
                             @JsonProperty("instanceType") String instanceType) {
            super(id, name);
            this.availabilityZone = availabilityZone;
            this.instanceType = instanceType;
        }

        @Override
        public String toString() {
            return "CloudInstance{" +
                    "availabilityZone='" + availabilityZone + '\'' +
                    ", instanceType='" + instanceType + '\'' +
                    '}';
        }
    }

    public static final String JSON = "{\n" +
            "        \"id\": null,\n" +
            "        \"siteName\": \"demo\",\n" +
            "        \"instances\": [\n" +
            "            {\n" +
            "                \"@type\": \"cloud\",\n" +
            "                \"instanceId\": \"i-8c2ee5fc\",\n" +
            "                \"name\": \"some-node\",\n" +
            "                \"availabilityZone\": \"some-zone\",\n" +
            "                \"instanceType\": \"t1.micro\"  \n" +
            "            }," +
            "            {\n" +
            "                \"@type\": \"simple\",\n" +
            "                \"instanceId\": \"ABC\",\n" +
            "                \"name\": \"FGF\"\n" +
            "            }]" +
            "   }";
    public static void main(String[] args) throws IOException {
        ObjectMapper mapper = new ObjectMapper();
        mapper.registerSubtypes(CloudInstance.class);
        System.out.println(mapper.readValue(JSON, Site.class));
    }

}
Site{siteName='demo', instances=[CloudInstance{availabilityZone='some-zone', instanceType='t1.micro'}, Instance{name='FGF'}]}
How to check for missing field in JSON using JSON.NET

How to check for missing field in JSON using JSON.NET


By : Owen Cain
Date : March 29 2020, 07:55 AM
This might help you The simplest option would be to make it an int? property, then check whether the value is null afterwards:
code :
public class SomeClass
{
    public string Foo { get; set; }
    public int? Bar { get; set; }
}

...

var deserialized = JsonConvert.DeserializeObject<SomeClass>(json);
if (deserialized.Bar == null)
{
    // Whatever you want to do if it wasn't set
}
How to check if a string in one field exist in every element of a comma separated field

How to check if a string in one field exist in every element of a comma separated field


By : Hugo
Date : March 29 2020, 07:55 AM
This might help you I have a table which contains two fields. The first is name of type string. The second contains one or more strings separated by comma (but it can contain a single string with no commas at all) , Try this regular expression:
code :
where not concat(names, ',') regexp replace('^([^,]*{n}[^,]*,)*$', '{n}', name)
Json schema django rest framework, describe json field as json and not as string

Json schema django rest framework, describe json field as json and not as string


By : user2901551
Date : March 29 2020, 07:55 AM
This might help you Sorry this is not possbile with JSON Schema.
The types are the primitive types allowed by JSON.
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