Pandas concat doesn't work as expected when one DF is created using a for loop

Pandas concat doesn't work as expected when one DF is created using a for loop

By : Shakir R
Date : November 22 2020, 04:01 AM
I hope this helps . Problem is you cast columns to strings, sa DataFrame cannot be aligned, because different columns names:
code :
for t in np.arange(10):
    #casting to string 
    samples_2[str(t)] = np.random.choice(datasort,2)

print (sample_1.columns)
RangeIndex(start=0, stop=10, step=1)
print (samples_2.columns)
Index(['0', '1', '2', '3', '4', '5', '6', '7', '8', '9'], dtype='object')
for t in np.arange(10):
    samples_2[t] = np.random.choice(datasort,2)

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Javascript - concat string does not work as expected

Javascript - concat string does not work as expected

By : demaxman
Date : March 29 2020, 07:55 AM
it fixes the issue What's the wrong with this Javascript line? ,
alert(user + "X") shows only h.reem
onclick of links created using a loop doesnt work

onclick of links created using a loop doesnt work

By : Kiran Kaur
Date : March 29 2020, 07:55 AM
C++ string array & for loop doesnt work as i expected

C++ string array & for loop doesnt work as i expected

By : s7aby.com
Date : March 29 2020, 07:55 AM
will be helpful for those in need You are confused about the character '1' and the number 1. They are different.
Instead of
code :
  if(num[a]==1 || num[a]==3 || num[a]==5 || num[a]==7 || num[a]==9)
  if(num[a]=='1' || num[a]=='3' || num[a]=='5' || num[a]=='7' || num[a]=='9')
char num[10] = {0};
#include <iostream>
using namespace std;

int main()
   cout << "Odd or Even"<< endl;
      char num[10] = {0};
      int a;
      cout << "Enter Number:" ;
      cin >> num;
      cout << endl;
         if(num[a]!='\0' && num[a]!=' ')
      cout << num[a] << endl;
      if(num[a]=='1' || num[a]=='3' || num[a]=='5' || num[a]=='7' || num[a]=='9')
         cout << "Odd" << endl;
         cout << "Even" << endl;
         if(num[a]!='\0' && num[a]!=' ')
Changing array element value from within loop doesnt work as expected

Changing array element value from within loop doesnt work as expected

By : Khanyi
Date : March 29 2020, 07:55 AM
this will help You have several issues. First you are counting array indexes from zero to the number of elements. When that is 4 then you go from 0 - 4, which is 5 elements, so you get an extra one. When it is fewer than 4 then it won't add the 'Unknown' because you are not iterating far enough.
Second, when you print an array using [*] inside quotes, the delimiter between elements is the first character of $IFS, which by default is a space:
code :
    echo "$1|$2|$3|$4"

    for ((i=0; i < 4; i++))
        if [[ -z ${paramArr[i]} ]];

    echo "${paramArr[*]}"

print_status Running 3.345 -0.076
print_status 'Not Running'
Not Running|||
Not Running|Unknown|Unknown|Unknown
Why does string concat apply not work as expected?

Why does string concat apply not work as expected?

By : user7888626
Date : March 29 2020, 07:55 AM
it should still fix some issue The first argument of apply is the context, which needs to be the string. You'd use
code :
const arr = ["2","3"];
console.log(String.prototype.concat.apply("1", arr));
console.log("".concat.apply("1", arr));
function concat(x, ...args) {
    return x.concat(...args);
function concat(x) {
    var args = Array.prototype.slice.call(arguments, 1);
    return x.concat.apply(x, args);
//                        ^
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