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Are There Restrictions on What can be Passed to auto Template Parameters?


Are There Restrictions on What can be Passed to auto Template Parameters?

By : user2185806
Date : November 22 2020, 04:01 AM
wish of those help In C++17, the restriction can be found in [temp.param]/4:
code :


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Parameters not being passed into template when using the .Net transform classes

Parameters not being passed into template when using the .Net transform classes


By : Venuz Gonzalez
Date : March 29 2020, 07:55 AM
I hope this helps . There is nothing strange -- this is the expected behavior of any XSLT 1.0 -compliant processor.
Explanation: The $nodeset variable defined as:
code :
<xsl:apply-templates select="$nodeset" mode="AParticularMode">
  <xsl:with-param name="paramA" select="'valueA'"/>
</xsl:apply-templates>
<xsl:template match="*|/">
  <xsl:apply-templates/>
</xsl:template>
<xsl:template match="*|/" mode="m">
  <xsl:apply-templates mode="m"/>
</xsl:template>
<xsl:template match="/" mode="AParticularMode">
  <xsl:param name="paramA"/>

  <xsl:apply-templates mode="AParticularMode">
    <xsl:with-param name="paramA" select="$paramA"/>
  </xsl:apply-templates>
</xsl:template>
Is there a good way to enforce type restrictions on function parameters in a variadic template in C++?

Is there a good way to enforce type restrictions on function parameters in a variadic template in C++?


By : Andrew
Date : March 29 2020, 07:55 AM
This might help you One easy way to do it would be to create a mapping from the enumerators to the desired types and use that to build the function parameter list - you could think of it as "enumerator traits", I guess:
code :
#include <iostream>
#include <string>

enum Type {STRING, TYPE_A_INT, TYPE_B_INT};

template<Type> struct type_from;

template<> struct type_from<STRING> { using type = std::string; };
template<> struct type_from<TYPE_A_INT> { using type = int; };
template<> struct type_from<TYPE_B_INT> { using type = int; };

template<Type E> using type_from_t = typename type_from<E>::type;

template<Type... Es> void Foo(type_from_t<Es>... args)
{
   // Do stuff with args.
   using expander = int[];
   (void)expander{0, (std::cout << args << ' ', 0)...};
   std::cout << '\n';
}

int main()
{
   Foo<STRING, TYPE_A_INT>("str", 32); // works
   Foo<STRING, TYPE_B_INT>("str", 32);  // works
   Foo<STRING, TYPE_B_INT, TYPE_A_INT, STRING>("str", 32, 28, "str");  // works
   // Foo<STRING, TYPE_B_INT>("str", "str");  // doesn't work
}
How to use both a uri and passed in parameters for a linked template?

How to use both a uri and passed in parameters for a linked template?


By : sunnyday
Date : March 29 2020, 07:55 AM
Hope that helps I think the root problem you're trying to get around is passing both parameters and linked parameters to a nested deployment... I can think of a few options, none are very elegant:
have your deployment script read the linked json file params and use all params in the nested deployment have your deployment script write your param files with the location and sasToken before staging them write the location and sasToken to a deployment output, and reference them from the output rather than as a parameter write the location and sasToken to keyvault and put the parameter reference to keyvault in your linked param file - this is tricky since you'd have to know the vault reference before deployment (when you create your param file).
C++ Template; Auto deduction return type of function passed as template argument;

C++ Template; Auto deduction return type of function passed as template argument;


By : user3336784
Date : March 29 2020, 07:55 AM
wish helps you What you are looking for is result_type, probably:
code :
//...
public:
  using TValue =  typename TGetter::result_type;
//...
How to extract the types passed in template parameters?

How to extract the types passed in template parameters?


By : Daymorn
Date : March 29 2020, 07:55 AM
should help you out What about a template taking a template?
With the following line you can declare a template taking a template and have the latter's template arguments types named:
code :
template<
template<typename, typename> class D, 
          typename A, typename B>
using namespace std;
template<class A, class B>
class C{
    public :
        A a;
        B b;
};
template<template<typename, typename> class T, typename A, typename B>
class M{
    public :
        B f;  //!!!!!!!!!!!!!!!!
        void show(){cout<<f;}
};
int main(){
    M<C, int, float> m;
    m.show();
}
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