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Add a node in xml using java only if the node has an attribute


Add a node in xml using java only if the node has an attribute

By : mfa
Date : November 24 2020, 04:01 AM
I hope this helps you . I have the following xml code and I want to add a note in node manufacturedMaterial only if it has the attribute determinerCode. , Can you check the list of attributes in the node?
code :
if(node.getAttributes().getNamedItem("determinerCode") != null)
{
    // Add your node here...
}


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XPATH / XSLT: Selecting a node where the parent node's attribute matches the attribute of another node

XPATH / XSLT: Selecting a node where the parent node's attribute matches the attribute of another node


By : user195434
Date : March 29 2020, 07:55 AM
Does that help As an alternative to using a variable, you can make use of the "current()" operator to get the current Author node you are on
code :
<xsl:value-of select="../Affiliation[@AFFID=current()/@AffiliationID]/OrgName"/>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
   <xsl:template match="/">
      <AUG>
         <xsl:for-each select="AuthorGroup/Author">
            <AU>
               <NAME>
                  <xsl:value-of select="./FamilyName"/>
                  <xsl:value-of select="./GivenName"/>
               </NAME>
               <AUINFO>
                  <xsl:value-of select="../Affiliation[@AFFID=current()/@AffiliationID]/OrgName"/>
               </AUINFO>
            </AU>
         </xsl:for-each>
      </AUG>
   </xsl:template>
</xsl:stylesheet>
<AUG>
   <AU>
      <NAME>SmithJohn</NAME>
      <AUINFO>Some Org</AUINFO>
   </AU>
   <AU>
      <NAME>AtkinsBill</NAME>
      <AUINFO>Another Org</AUINFO>
   </AU>
</AUG>
xsl and xpath : search for a node inside a node, and return the value of an attribute in the found node

xsl and xpath : search for a node inside a node, and return the value of an attribute in the found node


By : Awais Khalid
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I have the below xml : , A basic XPath expression that will extract what you need is
code :
//w:style[w:name/@w:val = 'Peter']/@w:styleId
<xsl:key name="nameByVal" match="w:name" use="@w:val" />
key('nameByVal', 'Peter')/../@w:styleId
key('nameByVal', 'Peter')/ancestor::w:style/@w:styleId
XSLT, do transformation for child node when the parent node attribute matches the value of an attribute of another node

XSLT, do transformation for child node when the parent node attribute matches the value of an attribute of another node


By : Paul de Joode Nitrob
Date : March 29 2020, 07:55 AM
help you fix your problem I have a source xml: , If I follow your instructions verbatim (AFAICT):
XSLT 1.0
code :
<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>

<xsl:key name="dataField" match="DataField" use="@name" />

<!-- identity transform -->
<xsl:template match="@*|node()">
    <xsl:copy>
        <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="/root">
    <xsl:copy>
        <xsl:apply-templates/>
        <xsl:apply-templates select="RegressionModel" mode="reg-tab"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="RegressionModel" mode="reg-tab">
    <xsl:variable name="targetVariable" select="@targetVariable" />
    <xsl:variable name="targetCategory" select="ParamMatrix/PCell[1]/@targetCategory" />
    <xsl:for-each select="key('dataField', $targetVariable)/Value[@value != $targetCategory]">
        <RegressionTable targetVariable="{$targetVariable}" targetCategory="{@value}" />
    </xsl:for-each>
</xsl:template>

</xsl:stylesheet>
<?xml version="1.0" encoding="UTF-8"?>
<root>
   <DataDictionary>
      <DataField name="CLASS">
         <Value value="0" property="valid"/>
         <Value value="1" property="valid"/>
         <Value value="2" property="valid"/>
      </DataField>
      <DataField name="COUNTRY_CODE">
         <Value value="1" property="valid"/>
         <Value value="2" property="valid"/>
         <Value value="3" property="valid"/>
      </DataField>
      <DataField name="MARITAL_STATUS">
         <Value value="1" property="valid"/>
         <Value value="2" property="valid"/>
         <Value value="3" property="valid"/>
      </DataField>
   </DataDictionary>
   <RegressionModel targetVariable="CLASS">
      <ParamMatrix>
         <PCell name="COUNTRY_CODE" targetCategory="0" coefficient="12"/>
         <PCell name="MARITAL_STATUS" targetCategory="0" coefficient="34"/>
      </ParamMatrix>
   </RegressionModel>
   <RegressionTable targetVariable="CLASS" targetCategory="1"/>
   <RegressionTable targetVariable="CLASS" targetCategory="2"/>
</root>
Process XML node by node but keeping node attribute from previous element

Process XML node by node but keeping node attribute from previous element


By : Elton Carreiro
Date : March 29 2020, 07:55 AM
hop of those help? You are not initializing the $header variable at the beginnig of each foreach pass, which leads to the fact that previous value is kept inside. Try this:
how to set the attribute of a node in java for Neo4j Node

how to set the attribute of a node in java for Neo4j Node


By : EmbeddedCookies
Date : March 29 2020, 07:55 AM
wish of those help Transaction.success only marks a transaction as successful. The transaction is not actually committed until Transaction.close() is called.
The Transaction JavaDocs states the following:
code :
try ( Transaction tx = graphDb.beginTx() )  {
    // operations on the graph
    // ...

    tx.success();
}
try (Transaction tx = db.beginTx()) {
    Node node = db.findNode(label, key, value);
    node.setProperty("k", 11);
    tx.success();
} 
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