Add result to int array every time you finish counting the occurrence

Add result to int array every time you finish counting the occurrence

By : sathvik desu
Date : November 25 2020, 04:01 AM
should help you out , You can do so using java-8, change the method to :
code :
public static int[] eStatistics(String[] names) {
    int[] newArray = new int[names.length];

    for (int i = 0; i < names.length; i++) {
        newArray[i] = (int) names[i].chars().filter(ch -> ch == 'e').count();

    return newArray;

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counting occurrence of numbers in array

counting occurrence of numbers in array

By : Александр Жадько
Date : March 29 2020, 07:55 AM
To fix this issue Another option is guava's Multiset classes, which will track the count for you:
code :
int values[] = ...;
Multiset<Integer> ms = HashMultiset.create();

int count0 = ms.count(Integer.valueOf(0));
int count1 = ms.count(Integer.valueOf(1));
Counting occurrence of 'every' number in array

Counting occurrence of 'every' number in array

By : user3508408
Date : March 29 2020, 07:55 AM
wish help you to fix your issue Check this DEMO.
I guess is what you want...
code :
int[] results = new int[100];

// fill map with results
for(int index = 0; index < randomNumbers.length; index++)
    // if number on randomnumbers is 2, this line sum +1 in position 2 of the array
    results[randomNumbers[index]] = results[randomNumbers[index]] + 1;
Counting occurrence of each value in an array

Counting occurrence of each value in an array

By : Dolly
Date : March 29 2020, 07:55 AM
I wish this help you Use findIndex along with reduce
findIndex will get the index of the object in the array where the name matches. If it is not -1 , there there does not exist any object whose name value matches with the array. If it exist then update the value of the frequency key
code :
var arrays = [{
  'id': 1,
  'name': 'Bob'
}, {
  'id': 1,
  'name': 'Bob'
}, {
  'id': 1,
  'name': 'Bob'
}, {
  'id': 2,
  'name': 'Jeff'
}, {
  'id': 1,
  'name': 'Bob'
}, {
  'id': 2,
  'name': 'Jeff'

let newArray = arrays.reduce(function(acc, curr, index) {
  let getIndex = acc.findIndex(function(item) {
    return item.name === curr.name;
  if (getIndex === -1) {
      name: curr.name,
      frequency: 1
  } else {
    acc[getIndex].frequency = acc[getIndex].frequency + 1

  return acc;
}, [])

C - Counting the occurrence of same number in an array

C - Counting the occurrence of same number in an array

By : Saman Saeedi
Date : March 29 2020, 07:55 AM
Any of those help You are really rather hamstrung by the order the values appear within buf. The only rudimentary way to handle this when limited to 4-values is to make a pass with nested loops to determine what the matching value is, and then make a single pass over buf again counting how many times it occurs (and since you limit to 4-values, even with a pair of matches, your count is limited to 2 -- so it doesn't make a difference which you count)
A short example would be:
code :
#include <stdio.h>

int main (void) {

    int buf[] = {1, 2, 5, 2},
        length = sizeof(buf) / sizeof(int), 
        count = 0,
        same = 0;

    for (int i = 0; i < length - 1; i++)    /* identify what value matches */
        for (int j = i + 1; i < length; i++)
            if (buf[i] == buf[j]) {
                same = buf[i];
                goto saved;     /* jump out of both loops when same found */
    saved:;    /* the lowly, but very useful 'goto' saves the day - again */

    for (int i = 0; i < length; i++)    /* count matching numbers */
        if (buf[i] == same)

    printf ("count = %d\n", count);

    return 0;
$ ./bin/arr_freq_count
count = 2
#include <stdio.h>
#include <string.h>
#include <limits.h>

int main (void) {

    int buf[] = {1, 2, 3, 4, 5, 2, 5, 6},
        n = sizeof buf / sizeof *buf,
        max = INT_MIN,
        min = INT_MAX;

    for (int i = 0; i < n; i++) {   /* find max/min for range */
        if (buf[i] > max)
            max = buf[i];
        if (buf[i] < min)
            min = buf[i];

    int range = max - min + 1;      /* max-min elements (inclusive) */
    int freq[range];                /* declare VLA */

    memset (freq, 0, range * sizeof *freq); /* initialize VLA zero */

    for (int i = 0; i < n; i++)     /* loop over buf setting count in freq */

    for (int i = 0; i < range; i++) /* output frequence of values */
        printf ("%d occurs %d times\n", i + min, freq[i]);

    return 0;
$ ./bin/freq_arr
1 occurs 1 times
2 occurs 2 times
3 occurs 1 times
4 occurs 1 times
5 occurs 2 times
6 occurs 1 times
Counting occurrence of specific value in an Array with PHP

Counting occurrence of specific value in an Array with PHP

By : LexArt
Date : March 29 2020, 07:55 AM
wish of those help I am trying to find a native PHP function that will allow me to count the number of occurrences of a particular value in an array. I am familiar with the array_count_values() function, but that returns the count of all values in an array. Is there a function that allows you to pass the value and just return the instance count for that particular value? For example:
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