JavaFX - method that waits for user input

JavaFX - method that waits for user input

By : NoSuchFileOrDirector
Date : November 26 2020, 04:01 AM
I hope this helps . Sounds like you're waiting for input on the main thread, which will block it thus your window freezes. Try putting the waiting code (nextToken method) in a separate thread.
code :

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Inactive form and waits for user input and then activate again

Inactive form and waits for user input and then activate again

By : Hemalatha P
Date : March 29 2020, 07:55 AM
help you fix your problem The behavior you describe is that of a model form. A model form is opened by a parent form and, while shown, prevents the parent form from being interacted with.
You can create a new form and show it as model like this:
code :

Form childForm = new ChildForm();
int result = childForm.Result;


public int Result;

void OnSubmitButtonPressed(object sender, EventArgs e)
    Result = inputBox.Value;
Why does not second function waits for user input?

Why does not second function waits for user input?

By : MPP
Date : March 29 2020, 07:55 AM
Any of those help Sound's like after doing std::copy() with std::cin leaves the input stream in failed state after (which is OK, otherwise the copy loop wouldn't end).
Put a
code :
Program that either waits for user input or runs at defined intervals?

Program that either waits for user input or runs at defined intervals?

By : user3540098
Date : March 29 2020, 07:55 AM
it helps some times The solution provided by clindseysmith introduces one more key press than what the original question was asking for (at least, my interpretation thereof). If you really want to combine the effect of the two snippets of code in the question, i.e., you don't want to have to press Ctrl+C for calling the file checker immediately, here's what you can do:
code :
import time, threading

def filechecker():
    #check for new files in a directory and do stuff
    print "{} : called!".format(time.ctime())

INTERVAL = 5 or 1800
t = None

def schedule():
    global t
    t = threading.Timer(INTERVAL, schedule)

    while True:
        print '{} : Sleeping... Press Ctrl+C or Enter!'.format(time.ctime())
        i = raw_input()
except KeyboardInterrupt:
    print '{} : Stopped.'.format(time.ctime())
    if t: t.cancel()
(Serial.available() > 0) waits for user input

(Serial.available() > 0) waits for user input

By : user2732770
Date : March 29 2020, 07:55 AM
should help you out Serial::Available() does not block. If there are characters available, readStringUntil() will be called, but that will not return until a newline is available - so that is where your blocking on input is likely to be occurring.
The following is perhaps a safer non-blocking solution:
code :
void checkIncomingOrder() 
    char ch = 0 ;
    while( ch != '\n' && Serial.available() > 0 ) 
        Serial.readBytes( &ch, 1 ) ; 
        order += ch ;

    if( ch == '\n' ) 
        Serial.println("Order is: " + order) ; 
        order = "" ;
        timer = 0 ;
void loop() 
I want to display a JOptionPane user input box in my start method of Application class (JavaFX)

I want to display a JOptionPane user input box in my start method of Application class (JavaFX)

By : Sujana Patel
Date : March 29 2020, 07:55 AM
seems to work fine Why you shouldn't use a JOptionPane
Don't use a JOptionPane in a JavaFX application.
code :
import javafx.application.Application;
import javafx.scene.control.TextInputDialog;
import javafx.stage.Stage;

import java.util.Optional;

public class TextInputDialogExample extends Application {
    private Optional<String> getValueFromUser() {
        TextInputDialog dialog = new TextInputDialog("xyzzy");

        dialog.setTitle("Value Input");
        dialog.setHeaderText("Enter a value:");

        return dialog.showAndWait();

    public void start(Stage stage) {
        Optional<String> value = getValueFromUser();


    public static void main(String args[]) {
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