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What is the difference between i++ & ++i in a for loop?


What is the difference between i++ & ++i in a for loop?

By : Munirathnam
Date : October 26 2020, 11:51 AM
With these it helps They both increment the number. ++i is equivalent to i = i + 1.
i++ and ++i are very similar but not exactly the same. Both increment the number, but ++i increments the number before the current expression is evaluted, whereas i++ increments the number after the expression is evaluated.
code :


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Difference between printing array returned from toarray() method using enhanced for loop and traditional for loop

Difference between printing array returned from toarray() method using enhanced for loop and traditional for loop


By : user2745641
Date : March 29 2020, 07:55 AM
wish help you to fix your issue The toArray(a) method returns the converted array and that's what you should be using; it didn't use your array since it wasn't large enough.
That is,
code :
for(Integer i : a)
{
  System.out.println(i);
}
for(int i : a)
{
  System.out.println(i);
}
for(int i : a)
{
  System.out.println(a[i]);
}
for(int i = 0; i < a.length; i++)
{
  System.out.println((int) a[i]);  // a[i] is null here, so casting causing an NPE
}
for(int i = 0; i < a.length; i++)
{
  System.out.println(a[i].intValue()); // a[i] is null here, causing an NPE
}
In a for loop, is there a difference between pre/post-incrementing a loop control variable in terms of the total quantit

In a for loop, is there a difference between pre/post-incrementing a loop control variable in terms of the total quantit


By : Yury
Date : March 29 2020, 07:55 AM
To fix this issue There is no difference. In older compilers, ++counter was faster because it did not create a temporary variable but all modern compilers can optimize that out. For heavy objects with custom (non-inlined) increment operators, ++counter can still be more efficient.
As for when evaluation takes place:
code :
for (initialization; condition; increment/decrement)
    code;
{
    initialization;
    while (condition)
    {
        code;
        increment/decrement;
    }
}
How to stop a MATLAB while-loop when the difference between two loop calculated values becomes small

How to stop a MATLAB while-loop when the difference between two loop calculated values becomes small


By : Zirke
Date : March 29 2020, 07:55 AM
I hope this helps . I currently am working on a school project where I need to calculate the terminal velocity of a sphere falling through liquid as well as how long it takes to reach terminal velocity. Terminal velocity is considered to be reached when the difference between two calculated velocities is less than .0001 m/s. The equation is a function of time and I am planing on using a while loop to perform this being I do not know how long it will take to be reached. I was planning on bumping up my time variable by .1 seconds after each loop. However, I do not know how to stop the loop as I do not know what the velocity will be. It would be very helpful if anyone could point me in the right direction with this. I am wondering how to stop the while loop or if there is another way to perform this calculation?
code :
while abs(OldVel - NewVel)>1e-4
    NewVel = OldVel; %// make the current velocity the old one
    NewVel = (..)    %// calculate some new velocity
end
How delegate inside loop understands difference between local and loop variable

How delegate inside loop understands difference between local and loop variable


By : Johor Jara
Date : March 29 2020, 07:55 AM
This might help you
Looking at the IL code I tend to think that compiler creates only one instance of myLocalVariable.
code :
static void F() {
    for (int i = 0; i < 3; i++) {
        int x = i * 2 + 1;
        ...
    }
}
Why does adding extra check in loop make big difference on some machines, and small difference on others?

Why does adding extra check in loop make big difference on some machines, and small difference on others?


By : Michael
Date : March 29 2020, 07:55 AM
To fix this issue One big difference between CPUs is the pipeline optimization
The CPU can execute in parallel several instructions until reaches a conditional branch. From this point instead of waiting until all the instructions are executed, the CPU can continue with a branch in parallel until the condition is available and ready to be evaluated. If the assumption was correct, then we have a gain. Otherwise the CPU will go with the other branch.
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