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Java variable number or arguments for a method


Java variable number or arguments for a method

By : Eli Raman
Date : October 23 2020, 11:12 PM
this will help That's correct. You can find more about it in the Oracle guide on varargs.
Here's an example:
code :


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How to conditionally pass parameters in Java to a method that takes a variable number of arguments?

How to conditionally pass parameters in Java to a method that takes a variable number of arguments?


By : Rajendra Patel
Date : March 29 2020, 07:55 AM
this will help I would suggest using the executeWithArray method: dynamically build up the array of parameters using an instance of java.util.ArrayList which you can then convert to an array using the toArray method. The code might look something like the following:
code :
ArrayList<Object> args = new ArrayList<Object>();
args.add(alphaP);
args.add(bravoP);
args.add(charlieP);
// Add other arguments here...

List<ResultClass> results = (List<ResultClass>) query.executeWithArray(args.toArray());
How can I create a Java method that accepts a variable number of arguments?

How can I create a Java method that accepts a variable number of arguments?


By : user3592292
Date : March 29 2020, 07:55 AM
This might help you For example, Java's own String.format() supports a variable number of arguments. , You could write a convenience method:
code :
public PrintStream print(String format, Object... arguments) {
    return System.out.format(format, arguments);
}
private void printScores(Player... players) {
    for (int i = 0; i < players.length; ++i) {
        Player player = players[i];
        String name   = player.getName();
        int    score  = player.getScore();
        // Print name and score followed by a newline
        System.out.format("%s: %d%n", name, score);
    }
}

// Print a single player, 3 players, and all players
printScores(player1);
System.out.println();
printScores(player2, player3, player4);
System.out.println();
printScores(playersArray);

// Output
Abe: 11

Bob: 22
Cal: 33
Dan: 44

Abe: 11
Bob: 22
Cal: 33
Dan: 44
Java reflection API and invoking a method with variable number of arguments

Java reflection API and invoking a method with variable number of arguments


By : user3707742
Date : March 29 2020, 07:55 AM
seems to work fine The varargs part is represented as String[] after compilation, so use String[].class
In your case it will be a bit harder, since you can't know exactly how many of the arguments there are before the varargs. So if you invoke showFoo str1 str2 str3 str4 you can't know how many string arguments there are before the varargs.
Call a Java-method with a variable number arguments from a Luafile with LuaJava

Call a Java-method with a variable number arguments from a Luafile with LuaJava


By : Driveman
Date : March 29 2020, 07:55 AM
help you fix your problem Unfortunately, Java arrays are not currently supported by LuaJava. It does not allow the construction of new Java arrays and does not support operations with arrays (getting and setting values). Therefore it is unable suport the Object... args syntax.
You could work around this by using specialized methods which take 0, 1, 2, 3 arguments (I do not think you would need more than 3). Then you would add a Lua vararg function which calls the appropriate function. An example for 3-argument call:
code :
public static void addEvent3( String luaFile, String function, 
                             int milliseconds, Object arg1, Object arg2, Object arg3 )
{
    events.add(new TimerEvent(luaFile, function, milliseconds, new Object[] {arg1, arg2, arg3}));
}
Get the number of variable arguments of a method in java

Get the number of variable arguments of a method in java


By : João Paulo Cordeiro
Date : March 29 2020, 07:55 AM
I hope this helps .
Because the arguments are passed as just regular arguments, not as arrays.
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