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Convert JSON style properties names to Java CamelCase names with GSON

By : Visitor112
Date : October 17 2020, 11:12 PM
around this issue I have found the following setting works perfect when reading json with underscored attributes and using camelcasing in my models.
code :

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How do I convert CamelCase into human-readable names in Java?

By : jeremy mccombs
Date : March 29 2020, 07:55 AM
it should still fix some issue I'd like to write a method that converts CamelCase into a human-readable name. , This works with your testcases:
code :
static String splitCamelCase(String s) {
   return s.replaceAll(
      " "
    String[] tests = {
        "lowercase",        // [lowercase]
        "Class",            // [Class]
        "MyClass",          // [My Class]
        "HTML",             // [HTML]
        "PDFLoader",        // [PDF Loader]
        "AString",          // [A String]
        "SimpleXMLParser",  // [Simple XML Parser]
        "GL11Version",      // [GL 11 Version]
        "99Bottles",        // [99 Bottles]
        "May5",             // [May 5]
        "BFG9000",          // [BFG 9000]
    for (String test : tests) {
        System.out.println("[" + splitCamelCase(test) + "]");
  XMLParser   AString    PDFLoader
    /\        /\           /\
 MyClass   99Bottles
  /\        /\
 GL11    May5    BFG9000
  /\       /\      /\

How can I deserialize JSON to Java Object using GSON when the JSON using dates as property names?

By : user3545540
Date : March 29 2020, 07:55 AM
I hope this helps you . I have a JSON response that I want to deserialize using GSON. The JSON structure uses date strings as property names. How would one go about deserializing such. , In my answer I considered you can have a JSON response like that:
code :
    "2015-04-23": [
            "seqNum": 1,
            "distance": 13,
            "start": "123 Main St",
            "end": "225 Broadway"
            "seqNum": 2,
            "distance": 21,
            "start": "225 Broadway",
            "end": "12 West St"

    "2015-04-24": [
                "seqNum": 1,
                "distance": 13,
                "start": "123 Main St",
                "end": "225 Broadway"
                "seqNum": 2,
                "distance": 21,
                "start": "225 Broadway",
                "end": "12 West St"
class MyObject {
    private List<DateMapping> dateMappings;

    public MyObject(List<DateMapping> dateMappings) {
        this.dateMappings = dateMappings;
class DateMapping {
    private Date date;
    private List<Sequence> sequences;

    public DateMapping(Date date, List<Sequence> sequences) {
        this.date = date;
        this.sequences = sequences;

class Sequence {
    private int seqNum;
    private int distance;
    private String start;
    private String end;
class MyObjectAdapter implements JsonDeserializer<MyObject> {

    private static final SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd");
    private static final Type listSequenceType = new TypeToken<List<Sequence>>(){}.getType();

    public MyObject deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context) throws JsonParseException {
        List<DateMapping> dateMappings = new ArrayList<>();
        for(Map.Entry<String, JsonElement> entry : json.getAsJsonObject().entrySet()) {
            try {
                dateMappings.add(new DateMapping(dateFormat.parse(entry.getKey()), context.deserialize(entry.getValue(), listSequenceType)));
            } catch (ParseException e) {
                throw new RuntimeException("Can't parse the date");
        return new MyObject(dateMappings);
Gson gson = new GsonBuilder().registerTypeAdapter(MyObject.class, new MyObjectAdapter()).create();
MyObject myObject = gson.fromJson(new FileReader(new File("myJson")), MyObject.class);
MyObject => 
DateMapping Thu Apr 23 00:00:00 CEST 2015, sequences=[Sequence{seqNum=1, distance=13, start='123 Main St', end='225 Broadway'}, Sequence{seqNum=2, distance=21, start='225 Broadway', end='12 West St'}]
DateMapping Fri Apr 24 00:00:00 CEST 2015, sequences=[Sequence{seqNum=1, distance=13, start='123 Main St', end='225 Broadway'}, Sequence{seqNum=2, distance=21, start='225 Broadway', end='12 West St'}]

Best way to convert Locale properties names to normal names

By : DefaultWorkgr0up
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I am reading a list of file property file names from a bundle. I need to replace file contents are in following format {en_GB==My name} , You can use
code :
String s = "{en_GB==pm!name}";
System.out.println(s.replaceAll("\\{\\w+=+([^}]+)}", "$1"));
System.out.println(s.replaceAll("(?i)\\{en_[a-z]+=+([^}]+)}", "$1"));
System.out.println(s.replaceAll("(?i)\\{en_[a-z]{2}=+([^}]+)}", "$1"));

Naming camelcase function names containing camelcase brand names

By : Bill Girten
Date : March 29 2020, 07:55 AM
To fix the issue you can do There's no general recommendation, your language might have guidelines that you might want to follow (doesn't seem the case with Node.js or javascript), or your company or application might have guidelines that you will have to follow, or there might be existing uses of the term in the application that you'll probably want to imitate, otherwise just use what seems easiest to read.
In this case, it might be isIOS, or isIos.

How to Pre Process Json String in Java :: Convert Capitalised Field names to lowerCase Camel case names

By : Jesuschn
Date : March 29 2020, 07:55 AM
I hope this helps . I think you should really consider letting your JSON deserializer handle this, but if this really isn't a possibility you can always use good old string manipulation :
code :
String input; // your JSON input
Pattern p = Pattern.compile("\"([A-Z])([^\"]*\"\\s*:)"); // matches '"Xxxx" :'
Matcher m = p.matcher(input);
StringBuffer output = new StringBuffer();
while (m.find()) {
   m.appendReplacement(output, String.format("\"%s$2", m.group(1).toLowerCase());
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