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Hot to get random date in range


By : Mohamed Mohamed
Date : October 17 2020, 11:12 PM
wish of those help You can convert the dates to Unix timestamp. Randomly pick a timestamp between the two timestamps and convert it back to date.
code :


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SQL Server : random date in specific range (including random hours, minutes,...)


By : user2668417
Date : March 29 2020, 07:55 AM
wish helps you This is how I'd do it:
Work out the number of seconds between from and to Get a random number between zero and the number of seconds Add that random number to the FromDate Finally randomise the number of milliseconds
code :
DECLARE @FromDate DATETIME = DATEADD(DAY, -2, GETDATE())
DECLARE @ToDate   DATETIME = DATEADD(DAY, -1, GETDATE())

DECLARE @Seconds INT = DATEDIFF(SECOND, @FromDate, @ToDate)
DECLARE @Random INT = ROUND(((@Seconds-1) * RAND()), 0)
DECLARE @Milliseconds INT = ROUND((999 * RAND()), 0)

SELECT DATEADD(MILLISECOND, @Milliseconds, DATEADD(SECOND, @Random, @FromDate))

How do you update an existing date to a random date in a range?


By : boroglass
Date : March 29 2020, 07:55 AM
To fix the issue you can do In one of my tables I have datetime field in which the data in the table column is populated with something like "2016-01-07 01:33:00". , Something like
code :
UPDATE someTable SET someDate = DATE_ADD(
    someDate,
    INTERVAL
        DATEDIFF(rangeStart, someDate) +
        ROUND(RAND()*DATEDIFF(rangeEnd, rangeStart))
    DAY
);

Java: Generate a random date between a range (range starting from current date/time to a random future date (e.g 5-10 da


By : Daniel Baker
Date : March 29 2020, 07:55 AM
will be helpful for those in need You can use LocalDateTime instead:
code :
import java.time.format.DateTimeFormatter;
import java.time.LocalDateTime;
import java.util.Random;

class Main {
  public static void main(String[] args) {
    // Declare DateTimeFormatter with desired format
    DateTimeFormatter dateTimeFormatter = DateTimeFormatter.ofPattern("yyyy/MM/dd HH:mm:ss");

    // Save current LocalDateTime into a variable
    LocalDateTime localDateTime = LocalDateTime.now();

    // Format LocalDateTime into a String variable and print
    String formattedLocalDateTime = localDateTime.format(dateTimeFormatter);
    System.out.println("Current Date: " + formattedLocalDateTime);

    //Get random amount of days between 5 and 10
    Random random = new Random();
    int randomAmountOfDays = random.nextInt(10 - 5 + 1) + 5;
    System.out.println("Random amount of days: " + randomAmountOfDays);

    // Add randomAmountOfDays to LocalDateTime variable we defined earlier and store it into a new variable
    LocalDateTime futureLocalDateTime = localDateTime.plusDays(randomAmountOfDays);

    // Format new LocalDateTime variable into a String variable and print
    String formattedFutureLocalDateTime = futureLocalDateTime.format(dateTimeFormatter);
    System.out.println("Date " + randomAmountOfDays + " days in future: " + formattedFutureLocalDateTime);
  }
}
Current Date: 2017/11/22 20:41:03
Random amount of days: 7
Date 7 days in future: 2017/11/29 20:41:03

Identify first & last date of Financial Year from list of random date range


By : user1100021
Date : March 29 2020, 07:55 AM
should help you out A non-VBA approach: you can use IF and MIN or MAX to create an array formula to do this (entered using Ctrl + Shift + Enter).
Since your FY begins on 01-Apr and ends on 31-Mar of the following year, I added two helper columns: "BEGINS" and "ENDS", with the relevant dates below.

Formula for returning random date within a range from a date in another column in Excel


By : user1705145
Date : March 29 2020, 07:55 AM
it fixes the issue =RANDBETWEEN(BOTTOM_NUMBER,TOP_NUMBER)
This will give you an integer greater than or equal to the bottom integer and less than of equal to the top number.
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