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C# string[] to int[]


C# string[] to int[]

By : rezatoune
Date : October 17 2020, 11:12 PM
With these it helps Is there a way to convert string arrays to int arrays as easy as parsing an string to an int in C#. , This linq query should do it:
code :


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Efficient conversion of Scala Map[String,Seq[String]] to java.util.Map<String,List<String>>

Efficient conversion of Scala Map[String,Seq[String]] to java.util.Map<String,List<String>>


By : jatinder singh
Date : March 29 2020, 07:55 AM
To fix this issue I am new to Scala, trying to integrate some existing Java code with Scala-specific functionality in the Play Framework. , Try this:
code :
import collection.JavaConverters._
val javaMap = scalaMap.mapValues(_.asJava).asJava
C# how to encode a long string in to fixed size string and again get back original string from encoded string?

C# how to encode a long string in to fixed size string and again get back original string from encoded string?


By : jóna kristjáns
Date : March 29 2020, 07:55 AM
Does that help That cannot work? When your reduce the length, information is lost.
The only thing possible is that you decide not to use the full spectrum of UTF-8. Lets assume you only you 7bit ASCII, This means the first 128 chars from the ASCII table. But that only make a length of 7 from a string of length 8. Maybe a bit more if you take into account the full power of UTF-8.
How to merge Stream<Map<String, Map<String, String>>> into a single Map<String, Map<String, Stri

How to merge Stream<Map<String, Map<String, String>>> into a single Map<String, Map<String, Stri


By : MobileCoderZmanx
Date : March 29 2020, 07:55 AM
it fixes the issue I am trying to merge a Stream>> object into a single map with keys in all the Streams. , When you have
code :
Stream<Map<String, Map<String, String>>> stream = ...
.flatMap(map -> map.entrySet().stream())
.collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue));
.collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue, (vOld, vNew) -> ...));
//                                                                                ^^^
Map<String, Map<String, String>> combinedMap = 
        /*your Stream<Map<String, Map<String, String>>>*/
        .flatMap(map -> map.entrySet().stream())
        .collect(Collectors.toMap(Map.Entry::getKey, Map.Entry::getValue));
How can I create Hashmap<String,Int : String,String : String,String> in Kotlin for sorting

How can I create Hashmap<String,Int : String,String : String,String> in Kotlin for sorting


By : user3440474
Date : March 29 2020, 07:55 AM
this one helps. I assume that chatMessages is of type List. This is generally bad because you cannot to anything with strings. I would suggest you to create a data class which contains all information about a chat message, like so:
code :
data class ChatMessage(val dateTime: Int, val userMail: String?, val userMessage: String?) : Comparable<ChatMessage> {
    override fun compareTo(other: ChatMessage) = this.dateTime.compareTo(other.dateTime)
}
private val chatMessages = mutableListOf<ChatMessage>()
data class ChatMessage(val dateTime:Int?, val userMail: String?, val userMessage: String?) : Comparable<ChatMessage> {
    override fun compareTo(other: ChatMessage) = this.dateTime.compareTo(other.dateTime)
}

private val chatMessages = mutableListOf<ChatMessage>()

fun yourCode() {
    newReference.addValueEventListener(object : ValueEventListener {

        /* Use proper variable naming. Nobody will understand, what p0 is, but if you name
        it dataSnapshot, everyone knows at a glance. */
        override fun onDataChange(dataSnapshot: DataSnapshot) {

            chatMessages.clear()

            // Again, what is ds exactly? Name it properly.
            for (ds in dataSnapshot.child(playerIDmatchWhoIs).children) {
                // Kotlin recommends to use val instead of var.
                // This way, you know that your variables cannot be modified unless you want them to be modified.
                val hashMap = ds.getValue() as HashMap<String, String>

                // use indexing instead of the get() method
                val dateTime = hashMap["datetime"]
                val userMail = hashMap["usermail"]
                val userMessage = hashMap["usermessage"]

                // TODO: Handle null values properly
                chatMessages.add(ChatMessage(dateTime!!.toInt(), userMail, userMessage))
                recyclerViewAdapter.notifyDataSetChanged()

            }

            chatMessages.sort()
        }
    })
}
Dotnet Core - Getting a warning on 'string.Replace(string, string?)' saying use 'string.Replace(string, string?, System.

Dotnet Core - Getting a warning on 'string.Replace(string, string?)' saying use 'string.Replace(string, string?, System.


By : Tony
Date : March 29 2020, 07:55 AM
this will help just... tell it what comparison type you want; for example, for an ordinal-ignore-case replace:
code :
    .Replace("and", "&", StringComparison.OrdinalIgnoreCase)
    .Replace("substringof", string.Empty, StringComparison.OrdinalIgnoreCase)
    .Replace("(", string.Empty, StringComparison.OrdinalIgnoreCase)
    .Replace(")", string.Empty, StringComparison.OrdinalIgnoreCase)
    .Replace("'", string.Empty, StringComparison.OrdinalIgnoreCase)
    .Replace(" ", string.Empty, StringComparison.OrdinalIgnoreCase)
    .Replace("eq", ",", StringComparison.OrdinalIgnoreCase);
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