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Should I declare the expected size of an array passed as function argument?


By : user3851309
Date : October 17 2020, 11:12 AM
it fixes the issue The main reason to add an array size is for documentation purposes. Also, with C99, you can add qualifiers within the square brackets which will be used to modify the pointer declaration to which the array declaration will be converted if it occurs within a parameter list.
See C99 spec, section 6.7.5.3, §7:
code :


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How to find out the size of an array when it is passed as an argument for the function?


By : Rajat
Date : March 29 2020, 07:55 AM
With these it helps Arrays decays into pointers when you pass to a function. With pointer alone, you can not get the size of the array. You have to pass one more argument to the calling function which is the size of the array. Example:
code :
#include <stdio.h>
void test(int myArray[10], int size)
{
    printf("Size of myArray = %d\n", size);
}
void fun(int myArray[10])
{
    int i = sizeof(myArray);
    printf("Size of myArray = %d\n", i);
}
// This function prints the output 4 
int main(void)
{
    int myArray[10] = {0}; 
    fun(myArray);
    test(myArray, sizeof(myArray));
    getchar();            ^----------------Here you are passing the size
    return 0;
}

Shell script loop over array passed as argument to multi-argument function?


By : Ivan
Date : March 29 2020, 07:55 AM
will help you I am trying to do something like this: , Revised Question
Replace:
code :
install 'brew install' $brews
install 'brew cask install' $casks
install 'brew install' "${brews[@]}"
install 'brew cask install' "${casks[@]}"
$ brews=(git node scala sbt zsh caskroom/cask/brew-cask)
$ echo $brews
git
$ echo "${brews[@]}"
git node scala sbt zsh caskroom/cask/brew-cask
if $cmd $2; then
if $cmd "$pkg"; then
for pkg in $@;
for pkg in "$@";

Getting size of an array passed in as an argument


By : user3598460
Date : March 29 2020, 07:55 AM
this one helps. Of course, you can do it - it's just len is not a field, it's a method:
code :
fn test_length(arr: &[String]){
    if arr.len() >= 10 {
        // Do stuff
    }
}
fn test_length(arr: &str) {
    if arr.len() >= 10 {
        // Do stuff
    }
}

How to declare a function that has a structure containing an array, whose size is determined by argv, as an argument?


By : Jacob Chen
Date : March 29 2020, 07:55 AM
I wish this help you I have a structure dt that contains an internal array whose size is determined by argv. I need to feed this structure to a function func so I tried to declare it with a void pointer argument but the compiler is complaining that it's not being void at the end of the day. Here is the code : , Try This:
code :
#include <stdio.h>
#include <string.h>

#define MAX_OBJECT 100
typedef struct
{
    char name[6];
    char ret[];
} dt;

void func(dt *strPtr)
{
    strPtr->ret[2] = 3;
}

int main(int argc, char *argv[])
{
    dt obj[MAX_OBJECT];

    func(&obj[0]);

    printf("Verify values written successfully or not: %d \n",obj[0].ret[2]); //Just for example
}

How to declare argument type in method when argument passed is an array of different objects?


By : Gale Frances Veleña
Date : March 29 2020, 07:55 AM
this will help One idiomatic approach would be to create an interface (or an abstract class) for both GroundEnemy and FlyingEnemy.
For instance:
code :
public interface Enemy { ... }
public class GroundEnemy implements Enemy { ... }
public class FlyingEnemy implements Enemy { ... }
private void renderEnemy(Array<? extends Enemy> enemies, delta) { ... }
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