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iTextSharp - How to get the position of word on a page

By : user3851334
Date : October 17 2020, 11:12 AM
I hope this helps you . Yes there is. Check out the text.pdf.parser package, specifically LocationTextExtractionStrategy. Actually, that might not do the trick either. You'll probably want to write your own TextExtractionStrategy to feed into PdfTextExtractor:
code :

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VBA for Word - position text boxes based on page

By : Lyuwei
Date : March 29 2020, 07:55 AM
this will help After adding a large number (150?) of callouts (simple text boxes in the margin, with no borders) to a Word 2010 .docx file with mirrored odd/even pages, I needed to adjust some text. This shortened the document enough to remove a page, and therefore all the odd pages following the adjustment became even, and the even became odd. The text boxes did not move, and now they all fall off the edge of the paper, where it is difficult even to find them all due to the text outside the bounds of the paper not being shown in the document, let alone to move them to their correct positions in the opposite margin. Moreover, I may need to adjust text again and the problem could recur.
code :
Sub AdjustTextBoxes()

Dim myTextBox As Shape
Dim PageNumber As Integer

For Each myTextBox In ActiveDocument.Shapes
    If myTextBox.Type = msoTextBox Then
        PageNumber = Selection.Information(wdActiveEndPageNumber)
        'Mod returns the remainder (rounded up) of the division.
        'No remainder is even. Any remainder is an odd page.
        If PageNumber Mod 2 = 1 Then
            With myTextBox 'Odd numbered pages
                .RelativeHorizontalPosition = wdRelativeHorizontalPositionPage 
                .Left = InchesToPoints(0.5)
            End With
            'Because wdRelativeHorizontalPositonPage measures from the left
            'edge of the page the positioning for text boxes on even pages
            'is not based on the distance from the right margin.
            'So below .Left = 8.5" (page width) - (1" (textbox with) + .5" (distance
            'from the right edge of the page). The measurement for .left below
            'will need to be altered based on the position from the right edge
            'of the page and the width of your text boxes and pages.
            With myTextBox 'Even numbered pages
                .RelativeHorizontalPosition = wdRelativeHorizontalPositionPage
                .Left = InchesToPoints(7)
            End With
        End If
    End If

End Sub

Efficiently generating all sequences by selecting word from position specific word pool at each position

By : Jandra Griškaitė
Date : March 29 2020, 07:55 AM
hop of those help? You don't really need any recursion.
The can enumerate all the possibilities like this:
code :
Initialize num_lists to number of word lists.
Initialize word lists per position.
Initialize max_count array for the number of words per position.
Initialize count array to all zeros.
  Print words corresponding to count array (count_array[0] select first word etc.)
  Carry = 1 // We're basically adding 1 to our counter
  Index = 0
  While Carry and Index<num_lists
    Add Carry to count[Index]
    If count[Index]==max_count[Index] then Carry=1; max_count[Index] = 0
    Else Carry = 0
    Index = Index + 1
While Carry==0

how to dynamically render a textbox value in asp.net web page into the same position in a PDF using iTextSharp?

By : user2293290
Date : March 29 2020, 07:55 AM
I wish did fix the issue. I had found out a way to tackle this, which I wanted to share.
A dynamic textbox value won't be rendered into a PDF automatically. So an invisible label is added along with the textbox inside the FormView. And in the button click of creating PDF, coded like below:
code :
    Dim nametxt As TextBox = DirectCast(FormView2.FindControl("TextBox5"), TextBox)

    Dim namelbl As Label = DirectCast(FormView2.FindControl("Label10"), Label)

    namelbl.Text = nametxt.Text

    namelbl.Visible = True

    nametxt.Visible = False

How To Position a Picture on A Second Page Of A Word Document VB6

By : docjo
Date : March 29 2020, 07:55 AM
may help you . Ok, So what worked for me was this:
Set oRng = oDoc.Bookmarks("\EndOfDoc").Range oRng.InsertBreak oDoc.Shapes.AddPicture "C:\Users\me\Desktop\file.jpg", , , CentimetersToPoints(1.3), CentimetersToPoints(0.9), CentimetersToPoints(6.1), CentimetersToPoints(2.9), oDoc.Bookmarks("\EndOfDoc").Range

Find the start and end position of a word in a string based on the index position of that word from a label list

By : user3015103
Date : March 29 2020, 07:55 AM
wish helps you I have a sentence , This should do it.
code :
def get(str,target_index):
  start = len(" ".join(str.split(" ")[:target_index])) + 1
  end = start + len(str.replace('.','').split(' ')[target_index])
  return (start,end)

str = 'cold weather gives me cold.' 
tag = ['O','O','O','O','disease']
start,end = get(str,tag.index('disease'))
print(start,end,str[start:end]) # outputs 22 26 cold

str = 'cold weather gives me cold'
tag = ['O','O','O','O','disease']
start,end = get(str,tag.index('disease'))
print(start,end,str[start:end]) # outputs 22 26 cold

str = 'cold weather gives me cold and cough' 
tag = ['O','O','O','O','disease']
start,end = get(str,tag.index('disease'))
print(start,end,str[start:end]) # outputs 22 26 cold
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