Moving from Linear Probing to Quadratic Probing (hash collisons)
By : Caspersky12
Date : March 29 2020, 07:55 AM
wish help you to fix your issue You don't have to modify the hash function for quadratic probing. The simplest form of quadratic probing is really just adding consequent squares to the calculated position instead of linear 1, 2, 3. There's a good resource here. The following is taken from there. This is the simplest form of quadratic probing when the simple polynomial c(i) = i^2 is used:

Linear Probing Hash Function not working?
By : Ruggero Visintin
Date : March 29 2020, 07:55 AM
should help you out You generally want a while loop until you find an empty slot. The other problem is you were equating a cell that your string hashes to being active to meaning that the cell contains the same value you are trying to insert. In general, you need to check the value of your key to insert against existing entries. It may be worth making an insert version that does not do this check for cases where the user can guarantee the item is not already in the hash table to avoid these comparisons... code :
bool HashTable_lp::insert( const string & x )
{
// Insert x as active
int currentPos = findPos( x );
while( isActive( currentPos ) ){
// here key gets out of array[currentPos] the string key
if(key(currentPos)==x) return true; // already in hash
currentPos++; // linearly probe to next guy
}
// at this point we know currentPos is empty
array[ currentPos ] = HashEntry( x, ACTIVE );
if( ++currentSize > array.size( ) / 2 ) // ensure load factor is .5 to guarantee probing works!
rehash( );
return false;
}

Quadratic probing over Linear probing
By : jetspeed
Date : March 29 2020, 07:55 AM
this one helps. You will stop searching the table when you hit an empty slot as you know that if you hit an empty slot, then the value you are looking for will not be in the hash table. Because of reduced clustering you will be more likely to hit an empty slot and stop searching. In addition, because of reduced clustering, you will be more likely when inserting to find an empty slot, causing in return to be able to more quickly search for that value.

How can quadratic probing fail to find a location on the next insertion while linear probing always finds one?
By : user3327518
Date : March 29 2020, 07:55 AM
Any of those help There must be a proof for this out there somewhere. But, I don't see how quadratic probing could hit every bucket in most cases. Let's say the table size is 7, and h(k) is 0. For the ith iteration, probe = i^2 mod 7. I tested all i less than 10,000 and this always evaluates to 0, 1, 2, or 4 for any i. Buckets 3, 5, and 6 will never be probed. code :
var hash_of_k = 0;
var table_size = 7;
var iteration_limit = 10000;
var buckets = new Object();
//Probe buckets
for(var i=0; i<iteration_limit; i++){
b = (hash_of_k+(i*i)) % table_size;
buckets[b] = 1;
}
//Report which buckets were probed.
var buckets_probed = '';
for(b in buckets){
buckets_probed += b + ' ';
}
alert(buckets_probed);

Linear probing not working for collision
By : ilong
Date : March 29 2020, 07:55 AM
I hope this helps . I am making a hash table based on reg no. The insertion function is working fine but the search and deletion doesn't work in case of collision. It's not doing anything at all. There aren't any compilation errors either. Any help would be appreciated. , The problem is in your inner loops. code :
else
for(i=0;i<k;i++)
{
else
for(int j=i+1;j<k;j++)
{

