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How to put c++ string into char array


How to put c++ string into char array

By : Joshua Diaz
Date : October 17 2020, 11:12 AM
I wish did fix the issue. If I have something like
code :


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Invalid conversion char to char* - Copying char in string array to another string array

Invalid conversion char to char* - Copying char in string array to another string array


By : Mohammadali Arabiyan
Date : March 29 2020, 07:55 AM
wish help you to fix your issue First of all, strcpy copies C strings (character arrays) not chars. Additionally, the lines strcpy(str_digit[i],str[i]) and strcpy(str_alpha[i], str[i]) would still probably be wrong even if this wasn't the case. Since you haven't initialised the arrays str_digit and str_alpha, you'll get a lot of garbage values while printing them and if any of those garbage values happen to be 0x00, the cout statements will fail to print the whole string. As already mentioned, you really should be using std::string rather than char[] or char*. Having said that, here are corrected versions of your code for both char[] and std::string.
Using gets is bad practice and you might consider using std::cin instead. And you might want to use an iterator rather than a simple for loop.
code :
//using char[]
#include <iostream>

using namespace std;

int main()
{
    char str[100] , str_alpha[100] , str_digit[100] ;
    int alpha_counter=0, digit_counter=0;

    cin.get(str, 99);

    for (int i=0 ; str[i] ; i++)
    {
        if(isalpha(str[i]))
        {
            str_alpha[alpha_counter] = str[i];
            alpha_counter++;
        }
        else if (isdigit(str[i]))
        {
            str_digit[digit_counter] = str[i];
            digit_counter++;
        }
    } 
    str_alpha[alpha_counter] = 0;
    str_digit[digit_counter] = 0;

    cout << "Alpha is " << str_alpha << endl ;
    cout << "Number is : " << str_digit << endl ;

    return 0;
}
//using std::string
#include <iostream>

using namespace std;

int main()
{
    string str, str_alpha , str_digit;

    cin >> str ;

    for (string::iterator it = str.begin();it<str.end();it++)
    {
        if(isalpha(*it))
        {
            str_alpha += *it;
        }
        else if (isdigit(*it))
        {
            str_digit += *it;
        }
    } 

    cout << "Alpha is " << str_alpha << endl ;
    cout << "Number is : " << str_digit << endl ;

    return 0;
}
difference beеween compare array of char and pointer to char string with char string

difference beеween compare array of char and pointer to char string with char string


By : devendra yadav
Date : March 29 2020, 07:55 AM
Hope that helps In both cases you are not comparing the actual strings (use strcmp for this), but addresses:
In the first case, you are comparing the address stored in a - the start address of a string literal "test" - with the start address of a (conceptually) different string literal, that happens to have the same content. However, if there are multiple identical string literals in your code, the compiler is allowed to store them all in the same place to save memory and as a result, the comparison yields true (although this is not guaranteed to happen every time). In the second case however, you are comparing the address of the first element of b with that of the string literal. Here, b is a local array that contains a copy of the string "test" but resides at a completely different memory region, so this comparison fails (and will always fail)
error setting variable to specific character in char array / string to char[] array to string[] array to string

error setting variable to specific character in char array / string to char[] array to string[] array to string


By : pengcheng
Date : March 29 2020, 07:55 AM
Hope this helps What you see here is a little bit of the code from a project that I am currently working on. I am making a BruteForce program because I was Challenged by my friend to test his login system on his website. , I found a way around my problem.
This sems to do the trick:
code :
Attempt = string.Concat(ArrayX[Eight].ToString().Replace(" ", string.Empty), ArrayX[Seventh].ToString().Replace(" ", string.Empty), ArrayX[Sixth].ToString().Replace(" ", string.Empty), ArrayX[Fifth].ToString().Replace(" ", string.Empty), ArrayX[Fourth].ToString().Replace(" ", string.Empty), ArrayX[Third].ToString().Replace(" ", string.Empty), ArrayX[Second].ToString().Replace(" ", string.Empty), ArrayX[First].ToString().Replace(" ", string.Empty));
how to create a string from char array by adding char by char in java

how to create a string from char array by adding char by char in java


By : Eddie V
Date : March 29 2020, 07:55 AM
Does that help If you use empty strings instead of null and initialize it then it works.
code :
String t = "foobarbaz";
int l = t.length();
char[] a;
a = new char[l];
String rel = ",";
String ret = "";
for (int i = 0; i<l; i++){
    a[i] = t.charAt(i);
}
for (int v = 0; v<l; v++){
    ret += a[v];
    ret += rel;
}
System.out.println(ret);
How to convert character array (char[]) to String array (String[]) without looping through char array and by using prede

How to convert character array (char[]) to String array (String[]) without looping through char array and by using prede


By : DAA
Date : March 29 2020, 07:55 AM
hope this fix your issue We can convert char[] to a String with below code:
code :
char[] charArray={'A','B','C'}; // Character array initialized
/**
   *Below line will first convert a charArray to string using 
   *String(char[]) constructor and using String class method  
   *split(regularExpression) the converted string will
   *then be splited with empty string literal delimiter which in turn 
   *returns String[] 
   **/
String[] result=new String(charArray).split("");
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