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How can this SQL query code be broken/exploited by user input?


How can this SQL query code be broken/exploited by user input?

By : user3851591
Date : October 16 2020, 11:12 AM
will be helpful for those in need , It could be exlpoited by backslashes.
code :


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Keeping code from being exploited, Securing Javascript and Forms

Keeping code from being exploited, Securing Javascript and Forms


By : user2347798
Date : March 29 2020, 07:55 AM
this will help First of all, thanks for the mention there and your most welcome.
How can locals() be exploited in python code?

How can locals() be exploited in python code?


By : user2930484
Date : March 29 2020, 07:55 AM
I wish this help you A simple example: If you have some magic ultra important encryption key enc_key in your local namespace of a webapp-view and you would use a user supplied string in this way:
code :
 a_var_that_gets_display = user_supplied_string % locals()
Django/Auth: Can request.user be exploited and point to other user?

Django/Auth: Can request.user be exploited and point to other user?


By : user6030793
Date : March 29 2020, 07:55 AM
seems to work fine The request.user object is of type SimpleLazyObject which is added by the auth middleware to the requestobject.
SimpleLazyObject(LazyObject): is used to delay the instantiation of the wrapped class At the time of requesting the actual logged in user, get_user method gets called.
code :
def get_user(request):
    if not hasattr(request, '_cached_user'):
        request._cached_user = auth.get_user(request)
    return request._cached_user
backend_path = request.session[BACKEND_SESSION_KEY]
backend = load_backend(backend_path)
user = backend.get_user(user_id) or AnonymousUser()
Can below PHP code be exploited?

Can below PHP code be exploited?


By : Mouna Soua
Date : March 29 2020, 07:55 AM
around this issue message can contain \n, so I could break order/flow if you depend on that, message length is not limited I could make you run out of space, there is no limit on message number, your IO is mine, message could contain XSS (like @Xorifelse mentioned), message could contain control character, that could be annoying e.g. with cat
How can Python 2's input() be exploited cause a comparison against a random number yet-to-be-generated to pass?

How can Python 2's input() be exploited cause a comparison against a random number yet-to-be-generated to pass?


By : irem
Date : March 29 2020, 07:55 AM
it should still fix some issue Approach 1: Overriding random.randint() Completely
Assuming the interpreter is Python 2, the following input will cause the result of the comparison to be True, without modifying the program at all:
code :
[42 for random.randint in [lambda x,y: 42]][0]
$ python test.py
What is the password?[42 for random.randint in [lambda x,y: 42]][0]
Access granted.
lambda x,y: 42
[42 for random.randint in [lambda x,y: 42]]
[random.seed(1), random.randint(0, 2**30), random.seed(1)][1]
$ python test.py
What is the password?[random.seed(1), random.randint(0, 2**30), random.seed(1)][1]
Access granted.
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