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Retrieving a resource file from an exe

By : user3851606
Date : October 16 2020, 11:12 AM
around this issue So you have a binary file embedded as a resource in an EXE, and you want to read the file?
Try something like this (very rough, look up functions on MSDN for proper parameters):
code :

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Description Resource Path Location Type error: Error retrieving parent for item: No resource found that matches the give

By : Dimitar Avramoski
Date : March 29 2020, 07:55 AM
may help you . AppCompat is a library project ans is missing. You need to reference the library project in your android project.
you can do one thing create a demo application in eclipse and make target same as your this application. it will automatic create a AppCompat lib. then add this lib to your project.

Retrieving resource id in Restlet

By : cba
Date : March 29 2020, 07:55 AM
I wish did fix the issue. If you define a path parameter when attaching a server resource, you can access its value within this server resource using the method getAttribute, as described below:
code :
public class ContactServerResource extends ServerResource {
    public Contact getContact() {
        String contactId = getAttribute("contactId");
public class ContactServerResource extends ServerResource {
    private Contact contact;

    protected void doInit() throws ResourceException {
        String contactId = getAttribute("contactId");
        // Load the contact from backend
        this.contact = (...)
        setExisting(this.contact != null);

    public Contact getContact() {
        return contact;

    public void updateContact(Contact contactToUpdate) {
       // Update the contact based on both contactToUpdate
       // and contact (that contains the contact id)

    public void deleteContact() {
       // Delete the contact based on the variable "contact"

Retrieving the headers of a file (resource) using urllib in Python 3

By : Anant Akash
Date : March 29 2020, 07:55 AM
Hope that helps HTTP has a special method named HEAD that tells the server to send only the headers (including Content-Length, if any) and stop right before the sending the actual content.
But to tell urllib to use the HEAD method, you should switch to the newer urlopen function:
code :
from urllib.request import Request, urlopen
resp = urlopen(Request('http://httpbin.org/html', method='HEAD'))
headers = resp.info()

Failing to use resource from Android library ("Error retrieving parent for item: No resource found that matches...&

By : Graham
Date : March 29 2020, 07:55 AM
hope this fix your issue Just resolved it by myself after finding out about publishing multiple variants.
In short: 1. Add
code :
android {...}

// Creates Gradle dependency configurations to use in the dependencies block.

configurations {
  // Initializes placeholder configurations that the Android plugin can use when targeting
  // the corresponding variant of the app.
  aDebugCompile {}
  bReleaseCompile {}

dependencies {
  // If the library configures multiple build variants using product flavors,
  // you must target one of the library's variants using its full configuration name.
  aDebugCompile project(path: ':my-library-module', configuration: 'aDebug')
  bReleaseCompile project(path: ':my-library-module', configuration: 'bRelease')

Retrieving a string value from a resource xml file using a key and getStringArray (Android)

By : user2055107
Date : March 29 2020, 07:55 AM
wish help you to fix your issue Are you working with the Android API? It seems that getStringArray isn't meant to work with a name attribute. It just returns an array containing the items text values.
So here, if you want to retrieve a i-th item of a t type, you could redesign your resource file this way:
code :
<?xml version="1.0" encoding="utf-8"?>
    <string-array name="kitchen">
    <string-array name="bathroom">
        <item>hair brush</item>
public final static int KITCHEN_ROOM = R.array.kitchen;
public final static int BATHROOM_ROOM = R.array.bathroom;

public String result(int room, int i)
    String[] roomItems =  roomID = getResources().getStringArray(room);
    // [room] + "_" + String.valueOf(item);

    if (rooms_items.length > i) return roomItems[i];

    // Here, you can throw an exception or return null;
    return null;
System.out.println(result(BATHROOM_ROOM,1)); // "hair brush"
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