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Exception in thread "main" java.lang.OutOfMemoryError: Java heap space


By : user3851695
Date : October 15 2020, 11:12 PM
I wish did fix the issue. Well, it's fairly self-explanatory: you've run out of memory.
You may want to try starting it with more memory, using the -Xmx flag, e.g.
code :


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Exception in thread "main" java.lang.OutOfMemoryError: Java heap space: Parsing dblp.xml


By : A. Müller
Date : March 29 2020, 07:55 AM
I wish did fix the issue. You are allocating not enough memory to the jvm.
I guess you set your parameter wrong because it is -Xmx900M and not -mx900M. The 'X' stands for non standard options.

How to handle "[ERROR] Exception in thread "main" java.lang.OutOfMemoryError: Java heap space" in JE


By : m.eric
Date : March 29 2020, 07:55 AM
may help you . I guess the problem is not to less memory for the java compile process but for the gwt-compiler. Increase the memory significantly here: org.codehaus.mojo gwt-maven-plugin ...
See: Codehaus.org gwt plugin usage

Error:Exception in thread "main" java.lang.OutOfMemoryError: Java heap space


By : Maonx
Date : March 29 2020, 07:55 AM
wish of those help When i == 2, the while loop will be executed forever and that's the reason why java.lang.OutOfMemoryError is thrown.
Add a break; after arrL.add(i);.

Exception in thread "main" java.lang.OutOfMemoryError: Java heap space if i'm scann many folder


By : CajunCoder
Date : March 29 2020, 07:55 AM
it should still fix some issue You would need to give more memory to jvm. You can find the process in following post.

Exception in thread "main" java.lang.OutOfMemoryError: Java heap space while using util Packages


By : Jon Gall
Date : March 29 2020, 07:55 AM
it fixes the issue My problem statement: , The problem is that this is an infinite loop:
code :
while(str != null) {
    char[] arr = new char[26];
    for(int i = 0; i < str.length(); i++) {
        arr[str.charAt(i) - 'a']++;              
    }
    String ns = new String(arr);
    if(map.containsKey(ns)){
        map.get(ns).add(str);
    } else {
        ArrayList<String> al = new ArrayList<String>(10000);
        al.add(str);
        map.put(ns, al);
    }
}
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