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How do I scan a folder in Java?


By : 임병완
Date : October 15 2020, 11:12 PM
may help you . java.io.File.list(FilenameFilter) is the method you're looking for.
code :


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How to scan a folder in Java?


By : johlton
Date : March 29 2020, 07:55 AM
like below fixes the issue Not sure how you want to represent the tree? Anyway here's an example which scans the entire subtree using recursion. Files and directories are treated alike. Note that File.listFiles() returns null for non-directories.
code :
public static void main(String[] args) {
    Collection<File> all = new ArrayList<File>();
    addTree(new File("."), all);
    System.out.println(all);
}

static void addTree(File file, Collection<File> all) {
    File[] children = file.listFiles();
    if (children != null) {
        for (File child : children) {
            all.add(child);
            addTree(child, all);
        }
    }
}
static void addTree(Path directory, Collection<Path> all)
        throws IOException {
    try (DirectoryStream<Path> ds = Files.newDirectoryStream(directory)) {
        for (Path child : ds) {
            all.add(child);
            if (Files.isDirectory(child)) {
                addTree(child, all);
            }
        }
    }
}
static void addTree(Path directory, final Collection<Path> all)
        throws IOException {
    Files.walkFileTree(directory, new SimpleFileVisitor<Path>() {
        @Override
        public FileVisitResult visitFile(Path file, BasicFileAttributes attrs)
                throws IOException {
            all.add(file);
            return FileVisitResult.CONTINUE;
        }
    });
}

How to scan a folder for files and their locations in java


By : user2738338
Date : March 29 2020, 07:55 AM
I wish this helpful for you Peek around in the java.io.File API. There are at least three methods which may be of use:
listFiles() isDirectory() isFile()

Java: Efficient way to scan a folder for a particular file


By : user2936139
Date : March 29 2020, 07:55 AM
This might help you There's no reason to recreate the File object. It just represents the file location, whether the file exists or not. Also you probably don't want a loop without at least a short delay, otherwise it'll just max out a processor until the file exists. You probably want something like this instead:
code :
File file = new File(filename);
while (!file.exists()) {
    Thread.sleep(100);
}

VB.Net Scan Folder & SubFolder for word 5.5 .DOCs and Save as RTF in a different Folder


By : user6636028
Date : March 29 2020, 07:55 AM
To fix the issue you can do Unfortunately I would use the paid converters if I was able but this is something that we are only able to use VB.net for.
I am unable to upload any samples of the documents or errors I can only describe them.

PHP > Scan folder/subfolder for images > generate array for every folder


By : Jesse O. Garcia
Date : March 29 2020, 07:55 AM
To fix the issue you can do You can try to make the array multidimensional by adding the folder name as key:
code :
foreach ($iterator as $fileinfo) {
    if (in_array($fileinfo->getExtension(), $extensions)) {
        $files[$fileinfo->getPath()][] = $fileinfo->getPathname();
    }
}
$files["path1"][0] = file1;
$files["path1"][1] = file2;
$files["path2"][0] = file1;
$files["path2"][1] = file2;
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