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how to make certain that the queryset will be ordered by a valid field - django

By : user3851764
Date : October 15 2020, 11:12 PM
will help you You can force a queryset to validate by running str(qs.query). At that point you can catch the exception without causing it to query the db.
code :

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How do I properly make a Django QuerySet where some field has values in a list?

By : Tạ Trần Khánh
Date : March 29 2020, 07:55 AM
With these it helps To use OR, look into django's Q objects.
code :
Widget.objects.filter(Q(foo='red') | Q(foo='green'), **filterQuery)

Django - How to find which field(s) a queryset is being ordered by?

By : Shruti Pruthi
Date : March 29 2020, 07:55 AM
wish helps you You can get the list of ordering criteria, accessing the query object:
code :
>>> qs = Store.objects.order_by('name', '-id')
>>> print qs.query.order_by
['name', '-id']

Django queryset ordered by exisiting as OneToOne field in second model

By : Kleber Sato
Date : March 29 2020, 07:55 AM
like below fixes the issue You only want Foo object that have a Bar object linked to them, that mean: filter.
code :
Foo.objects.filter(bars__isnull=False).order_by('bars', '-date')
Foo.objects.filter(bars__isnull=False).order_by('bars__from_date', '-date')
foo = Foo.objects.get(id=1)
bars = foo.bars.all()
foo = Foo.objects.get(id=1)
bar = foo.bar

Trying to compare non-ordered queryset against more than one ordered values django

By : Jess
Date : March 29 2020, 07:55 AM
Hope this helps From docs:
code :
queryset = vote_form.cleaned_data['choice']
self.assertQuerysetEqual(list(queryset), ['<Choice: First choice>', ...])
queryset = vote_form.cleaned_data['choice']
self.assertQuerysetEqual(list(queryset), ['<Choice: First choice>', ...], ordered=False)

Django Queryset Iterator for Ordered queryset

By : Fazal Banani
Date : March 29 2020, 07:55 AM
it fixes the issue Here is mine, with sort function.
By the way the iterator you are using has a "forever loop" when in process the queryset items are modified: deleted or added, even one item.
code :
def queryset_iterator(queryset, chunksize=10000, key=None):
    key = [key] if isinstance(key, basestring) else (key or ['pk'])
    counter = 0
    count = chunksize
    while count == chunksize:
        offset = counter - counter % chunksize
        count = 0
        for item in queryset.all().order_by(*key)[offset:offset + chunksize]:
            count += 1
            yield item
        counter += count
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