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can java inputstream read files that are being updated in memory?


By : user3851772
Date : October 15 2020, 11:12 PM
I wish did fix the issue.
lets say we have a excel file that is being updated constantly. Without having to save that excel file, can we read its updated data? – vamsi
code :


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Java: InputStream too slow to read huge files


By : Rat
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , I have to read a 53 MB file character by character. When I do it in C++ using ifstream, it is completed in milliseconds but using Java InputStream it takes several minutes. Is it normal for Java to be this slow or am I missing something? , I ran this code with a 183 MB file. It printed "Elapsed 250 ms".
code :
final InputStream in = new BufferedInputStream(new FileInputStream("file.txt"));
final long start = System.currentTimeMillis();
int cnt = 0;
final byte[] buf = new byte[1000];
while (in.read(buf) != -1) cnt++;
in.close();
System.out.println("Elapsed " + (System.currentTimeMillis() - start) + " ms");

Does a Java InputStream help or hurt memory usage with large files?


By : Sohaib Cheema
Date : March 29 2020, 07:55 AM
I wish this help you I see some posts on StackOverflow that contradict each other, and I would like to get a definite answer. ,
So you are saying that an InputStream would typically help?
code :
  // Efficient use of memory
  try (InputStream is = new FileInputStream(largeFileName);
       BufferedReader br = new BufferedReader(new InputStreamReader(is))) {
      String line;
      while ((line = br.readLine()) != null) {
          // process one line
      }
  }

  // Inefficient use of memory
  try (InputStream is = new FileInputStream(largeFileName);
       BufferedReader br = new BufferedReader(new InputStreamReader(is))) {
      StringBuilder sb = new StringBuilder();
      while ((line = br.readLine()) != null) {
          sb.append(line).append("\n");
      }
      String everything = sb.toString();
      // process the entire string
  }

  // Very inefficient use of memory
  try (InputStream is = new FileInputStream(largeFileName);
       BufferedReader br = new BufferedReader(new InputStreamReader(is))) {
      String everything = "";
      while ((line = br.readLine()) != null) {
          everything += line + "\n";
      }
      // process the entire string
  }

SAXBuilder().build(InputStream) - does this read entire file into memory?


By : Thibault Lavoisey
Date : March 29 2020, 07:55 AM
With these it helps The DOM parser similarly to the JDom parser loads the whole XML resource in memory to provide you a Document instance allowing to navigate in the elements of the XML.
Some references here :

Why CXF / JAXB read whole InputStream into memory before marshalling to SOAP message


By : Leng Chiva
Date : March 29 2020, 07:55 AM
should help you out You don't need any custom marshallers or change JAXB behaviour to achieve what you need - DataHandler is your friend here.
Answering your first question: JAXB needs to keep all data in memory because it has to resolve references.

Java: How to count read bytes from InputStream without allocating the full memory before


By : Karthik
Date : March 29 2020, 07:55 AM
wish of those help You can use Guava's CountingInputstream or Apache IO's CountingInputStream when you want to know how many bytes have been read.
On the other hand when you want to stop the upload immediatly when reaching some limit then just count while reading chunks of bytes and close the stream when the limit has been exceeded.
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