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c++ figuring out memory layout of members programmatically


By : user3851784
Date : October 15 2020, 11:12 PM
I hope this helps . You need to research "serialization". There is a library, Boost Serialization, that people have been recommending.
FWIW, I recommend against using fwrite or std::ostream::write on classes, structures and unions. The compiler is allowed to insert padding between members, so there may be garbage written out. Also, pointers don't serialize very well.
code :


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struct members memory layout


By : user3654879
Date : March 29 2020, 07:55 AM
I wish this help you Yes, in C at least. The compiler is free to insert padding after any structure member but it must not reorder the members.
It must also not insert padding before the first member.

Figuring out the memory layout of objects without debugging a running program?


By : Tesa Carlson
Date : March 29 2020, 07:55 AM
To fix the issue you can do The vtable of a class is just a list of pointers to functions. It contains one pointer for each virtual function, in the order: very, very top base class, next base class, subclass of that, . . . most derived class.
Example:
code :
struct A {
    virtual ~A() {}
    virtual void foo() = 0;
}
struct B : public A {
    virtual void foo() { // do something }
    virtual void bar() { // do something else }
}

Are C-structs with the same members types guaranteed to have the same layout in memory?


By : Sabb
Date : March 29 2020, 07:55 AM
I wish did fix the issue.
Are C-structs with the same members types guaranteed to have the same layout in memory?
code :
struct a {
    int x;
    int y;
};

struct b {
    int h;
    int k;
};

union {
    struct a a;
    struct b b;
} u;
struct a { int x; };
struct b { int x; };
int test(int value)
{
    struct a a;
    a.x = value;
    return ((struct b *) &a)->x;
}

C++ POD struct inheritance? Are there any guarantees about the memory layout of derived members


By : Ayesha Khan
Date : March 29 2020, 07:55 AM
To fix this issue No, the layout is not guaranteed. The only guarantees are for standard-layout classes; and one of the conditions of such a class is that it

Memory layout of static and readonly members


By : Nitin Sharma
Date : March 29 2020, 07:55 AM
Any of those help Memory for static fields, constant or not, is never allocated per instance. Moreover, static const is not allowed - const is automatically considered one-per-class.
There are differences between const and static readonly fields, but neither one of them changes the footprint of instances of the corresponding class.
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